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4 years ago

Find the volume of an oblique cone.

Mathematics

1 answer:

AURORKA [14]4 years ago

8 0

V = (1/3) π r² t

= (1/3) π (10 cm)². 16 cm

= (1/3) π (100 cm²). 16 cm

= (1/3) π (1600 cm³)

= (1600π)÷3 cm³ (B)

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How can we describe the relationships that exist between circles and lines?

Lunna [17]

circles are 360⁰ and lines are 180⁰

5 0

2 years ago

Solve this system of linear equations. Separate the x- and y-values with a comma.

vodomira [7]

Answer:

x = $\frac{5}{2}$ , y = $\frac{5}{4}$

Step-by-step explanation:

1. Isolate for x in one of the equations:

2x = 9x - 14y

2x-9x = 9x-9x -14y

-7x = -14y

-7x/-7 = -14y/-7

x = 2y

2. Substitute 2y in for x in the second equation:

9(2y) = 40 - 14y

3. Simplify:

18y = 40 - 14y

4. Isolate for y:

18y+14y = 40 -14y+14y

32y = 40

32y/32 = 40/32

y = $\frac{5}{4}$

5. Substitute the new y-value into the simplified expression x = 2y:

x = 2(5/4)

x = $\frac{5}{2}$

hope this helps!

7 0

2 years ago

Joey decides to empty his piggy bank and count his money. His bank is filled with only nickels and dimes. Joey counted a total o

xxTIMURxx [149]

Answer:

Joey has 18 nickles and 27 dimes in his piggy bank.

Step-by-step explanation:

1 nickle = 5 cents

1 dime = 10 cents

$1 = 100 cents

$3.15 = 135 cents

Let

n represent the number of nickles, n>=0

d represent the number of dimes, d>=0

Joey counted a total of 45 coins that added up to $3.15:

n + d = 45

5n + 10d = 315

n = 18 nickles

d = 27 dimes

5 0

3 years ago

Is -32 an irrational number

dybincka [34]

Answer:
The answer is nope

8 0

3 years ago

Read 2 more answers

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

Hence proved.

4 0

3 years ago