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Doss [256]
3 years ago
12

Ravi made 4 identical necklaces each having beads and a pendant. The total cost of the beads and pendants are for all four neckl

aces are 26.40. If the beads cost a total cost of 13.20 how much did each pendant cost?
Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

Each pendant cost $3.30

Step-by-step explanation:

You would subtract $13.20 from $26.20  and get $13.20. You take $13.20 and divide it by 4. You would get $3.30.

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Find the volume of the cylinder. Either enter an exact answer in terms of T or use 3.14 for T. With a height of 3 and a radius o
kobusy [5.1K]

Answer:

235.5‬

Step-by-step explanation:

V = πr²h

V = 3.14 x 5² x 3

V = 3.14 x 25 x 3

V = 3.14 x 75

V = 235.5‬

8 0
3 years ago
what is the probability that a card picked at random from a 52-card deck of playing cards is a club or a jack?
ASHA 777 [7]

|\Omega|=52\\ |A|=\underbrace{13}_{\text{clubs}}+\underbrace{4}_{\text{jacks}}-\underbrace{1}_{\text{jack of clubs}}=16\\\\ P(A)=\dfrac{16}{52}=\dfrac{4}{13}\approx31\%

7 0
3 years ago
Read 2 more answers
Really easy....plz help if u can..will mark
goldenfox [79]

Answer:

The distributive property.

Step-by-step explanation:

The distributive property is when you distribute a number to different numbers in a parentheses. For example...

2*x would be 2x, and 2*4 would be 8.

4 0
3 years ago
HELP QUICK GIVING 50 POINTS!!!
avanturin [10]

Answer:

64/3 cc or 64/3 cm³

Step-by-step explanation:

The formula for the volume of a triangular pyramid is

V = (1/3)(area of base)(height)

Here we have a square prism (actually, a cube), whose square base is 4 cm by 4 cm (4 cm is the cube root of 64 cc).  The height of this cube is also 4 cm.

The volume of a triangular pyramid of base area (4 cm)² and height 4 cm is

V = (1/3)(base area)(height)

   = (1/3)(16 cm²)(4 cm) = 64/3 cc

8 0
3 years ago
Complete the tables of values.
Vladimir [108]

Answer:

a=1\\b=\frac{1}{16}\\\\c=\frac{1}{256}\\\\d=1\\e=\frac{4}{9}\\\\f=\frac{16}{81}

Step-by-step explanation:

For the orange table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function f(x)=4^{-x}, then:

For a:

x=0

f(0)=4^0=1

For b:

x=2

f(x)=4^{-2}=\frac{1}{16}

For c:

x=4

f(x)=4^{-4}=\frac{1}{256}

For the blue table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function g(x)=(\frac{2}{3})^x, then:

For d:

x=0

g(x)=(\frac{2}{3})^0=1

For e:

x=2

g(x)=(\frac{2}{3})^2=\frac{4}{9}

For f:

x=4

g(x)=(\frac{2}{3})^4=\frac{16}{81}

3 0
3 years ago
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