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3 years ago

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 65% and P(T) = 7%.

2 answers:

5 0

When you have two mutually exclusive events, to find the probability of one or another, you add the probabilities.
65+7=72
Final answer: B

MaRussiya [10]3 years ago

4 0

Answer: P(S\cup T)=72%

Step-by-step explanation:

We are given that S and T are mutually exclusive events.

Therefore, the intersection of both the events must be 0.

i.e. $p(S\cap T)=0$

P (S) = 65% and P(T) = 7%

We know that P(S or T)= $P(S\cup T)=P(S)+P(T)-P(S\cap T)$

$\Rightarrow P(S\cup T)=65\%+7\%=72\%$

Hence, P(S\cup T)=72%

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