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1 year ago

11

so if u drive to pick up three kids (to put in ur basement ofc) and then pick up 4 more then 7 more then 8 more then when pigs f

ly how much turbulance is needed to fly from antartica to mars??

2 answers:

Talja [164]1 year ago

6 0

Answer:

turbulence is needed?

Step-by-step explanation:

Yuliya22 [10]1 year ago

3 0

Answer:

32!

Step-by-step explanation:

You might be interested in

What slope is perpendicular to m= 5/8<br> m=-5/8<br> m=5/8<br> m=-8/5<br> m=8/5

MrRa [10]

Answer:

C) $m =\frac{-8}{5}$

The slope of the perpendicular line $m =\frac{-8}{5}$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the slope of the given line is

$m =\frac{5}{8}$

The slope of the perpendicular line

= $\frac{-1}{m}$

The slope of the perpendicular line

= $\frac{-1}{\frac{5}{8} }$

<u><em>Final answer</em></u>

The slope of the perpendicular line

$m =\frac{-8}{5}$

7 0

2 years ago

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0

2 years ago

Which expressions are equivalent to 7b(3+c) ?

aliya0001 [1]

C because it's using the distributive property. It's breaking it down into sections.

8 0

2 years ago

Two cards are chosen from a standard deck of 52 playing cards without replacement. What is the probability that the first card i

Rashid [163]

For the first draw, the probability of an ace is ( 4 / 52 ).

Now there are only 51 cards left in the deck.

For the second draw, the probability of a king is ( 4 / 51 ).

The probability of both events is

(4/52) (4/41) = (16/2,652)

Divide top and bottom by 4:

(16/2,652) = <em>4/663</em> . That's <em>choice-C </em>.

6 0

2 years ago

What is the sum of 1 2/5 and 5 3/4

Art [367]

Answer:

$7\frac{3}{20}$

Step-by-step explanation:

<em>Hey there!</em>

Well to add this we need to pu it in improper form.

7/5 + 23/4

Now we need to find the LCM.

5 - 5, 10, 15, 20, 25, 30

4 - 4, 8, 12, 16, 20, 24, 28

So the LCD is 20.

Now we need to change the 5 and 4 to 20.

5*4 = 20

7*4 = 28

<u>28/20</u>

4*5=20

23*5=115

<u>115/20</u>

Now we can add 28 and 115,

= 143/20

Simplified

7 3/20

<em>Hope this helps :)</em>

4 0

2 years ago

Read 2 more answers