Ask question

Ask question

All categories

3 years ago

11

so if u drive to pick up three kids (to put in ur basement ofc) and then pick up 4 more then 7 more then 8 more then when pigs f

ly how much turbulance is needed to fly from antartica to mars??

2 answers:

Talja [164]3 years ago

6 0

Answer:

turbulence is needed?

Step-by-step explanation:

Yuliya22 [10]3 years ago

3 0

Answer:

32!

Step-by-step explanation:

You might be interested in

Choose the correct solution and graph for the inequality.

Y_Kistochka [10]

The answer to question one would be "D" y<-3

For question two the answer would be "C" x<5

Hope that helps!

6 0

3 years ago

The graph of g(x)=(0.75)x+2 is shown.

Andrei [34K]

we are given

$f(x)=(0.75)^x+2$

For finding asymptote , we can find limit

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}((0.75)^x+2)$

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty} (0.75)^x+\lim_{x \to \infty} 2)$

now, we can solve it

$\lim_{x \to \infty} f(x)= 0+2$

$\lim_{x \to \infty} f(x)= 2$

so, horizontal asymptote is

$y= 2$ .............Answer

6 0

3 years ago

Write an equation for the orbit of Saturn in the form x^2/a^2 + y^2/b^2 = 1

frozen [14]

Answer:

x²/2166784 +y²/2159989 = 1

Step-by-step explanation:

The relationship between the semi-axes and the eccentricity of an ellipse is ...

e = √(1 -b²/a²)

In order to write the desired equation we need to find 'b' from 'e' and 'a'.

__

<h3>semi-minor axis</h3>

Squaring the equation for eccentricity gives ...

e² = 1 -b²/a²

Solving for b², we have ...

b²/a² = 1 -e²

b² = a²(1 -e²)

<h3>ellipse equation</h3>

Using the given values, we find ...

b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989

The desired equation is ...

x²/2166784 +y²/2159989 = 1

7 0

2 years ago

I need to know this plz and thank u

mr_godi [17]

The third one :) I hope I did it right

3 0

3 years ago

Read 2 more answers

If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo

Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or, Q = 40 kg × 4200 × 18

or, Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0

3 years ago