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Artyom0805 [142]
2 years ago
13

What is the center and radius of a circle whose equation is x2 + y2 -2x -6y -5 = 0?

Mathematics
1 answer:
ddd [48]2 years ago
4 0

x²+y²-2x-6y-5=0

x²-2x+y²-6y=5

x²-2x+1+y²-6y+9=5+1+9

(x-1)²+(y-3)²=15

(x-1)²+(y-3)²=(V15)²

-> centre of the circle: C(-1,-3)

-> radius of the circle: V15

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The graph of ƒ(x) = -√x is shifted to the right five units. The domain of the function represented by this graph is x ≥&gt;≤&lt;
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Given: f(x)=-\sqrt{x}

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3 years ago
For what value of x will the function f(x) = -3(x - 10)(x - 4) have a maximum value? Find the maximum value.
gayaneshka [121]

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To find the maximum value of the function f(x) = -3(x - 10)(x - 4), the easiest way is to find the vertex using the formula: x = -b/2a.

Firstly, we need to simplify f(x).

f(x) = -3(x - 10)(x - 4)

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The vertex of f(x) is (7, 27).

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