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Artyom0805 [142]
2 years ago
13

What is the center and radius of a circle whose equation is x2 + y2 -2x -6y -5 = 0?

Mathematics
1 answer:
ddd [48]2 years ago
4 0

x²+y²-2x-6y-5=0

x²-2x+y²-6y=5

x²-2x+1+y²-6y+9=5+1+9

(x-1)²+(y-3)²=15

(x-1)²+(y-3)²=(V15)²

-> centre of the circle: C(-1,-3)

-> radius of the circle: V15

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Find f(−5) if f(x)=|x+1|. Type a numerical answer in the space provided. Do not type spaces in your answer.
marin [14]
<h3>Answer:   4</h3>

===============================================

Work Shown:

f(x) = |x+1|

f(-5) = |-5+1| .... x is replaced with -5

f(-5) = |-4|

f(-5) = 4

6 0
2 years ago
Write the equation in standard form of a line that is parallel to the graph of 2x + y = 5 and whose y - intercept is (0,4).
babunello [35]

The line that is parallel to this line will have the same slope of this line, as the two will never intersect. They will run side by side. The line y = 2x - 5 is written in slope-intercept form, which is y = mx + b. The value of m represents the slope, and in this equation m = 2. Therefore, the line we are looking for will have a slope of 2 also.

That line should also be in slope-intercept form. We now know the value of m, but we also know the value of x and y. The ordered pair (8, 10) is a point on the line, and every ordered pair is in the form (x, y). Therefore, x = 8 and y = 10. We can plug those values into y = mx + b, along with m = 2. That gives us:

10 = 2(8) + b We need to solve for b.

10 = 16 + b

b = -6

5 0
2 years ago
Identify the similar triangles. Find each measure.​
boyakko [2]

Answer:

Example: these two triangles are similar: If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°. So AA could also be called AAA (because when two angles are equal, all three angles must be equal)

5 0
3 years ago
an ordered pair where the x and y coordinate are the same lies in the 1st or 3rd quadrant. true, sometimes true or not true?. ex
Zarrin [17]

The quadrants are as follows:

The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.

So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.

However, there is one special case:

When x and y are 0, that is, the ordered pair is (0, 0).

Since this point is the origin, it doesn't lie on any of the quadrants.

Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).

7 0
1 year ago
I'm having trouble
Liono4ka [1.6K]
It would be B because you would take amelias age and take two away since todd is five years younger to get the a-5.
hope this helps :)
8 0
3 years ago
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