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AfilCa [17]
1 year ago
7

Melinda has a goal of donating at least $300 to charity this year. Her mother and father each gave her $25 to help and she is se

lling ribbons for $5 each. What is the least number of ribbons Melinda must sell to reach her goal?​
Mathematics
1 answer:
yulyashka [42]1 year ago
8 0

Answer:

50

Step-by-step explanation:

25x2=50

300-50=250

250/5=50

50 ribbons needed :) hope this helped

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Ned rode his bike 7 miles to the library. he took a shortcut on the way home which was only 5 miles long. how many miles did ned
kondor19780726 [428]
He took 12 miles your welcome
4 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
Find the solutions x2 = 27​
Aneli [31]

Answer:

27  divided by 3 is 9

27 divided by 2 is 13.5

x = 13.5

Re written...

(13.5)2 = 27

make sense?

7 0
2 years ago
Find the measure of c.<br> (1<br> 27<br> O A. 31.6<br> B. 27<br> C. 63<br> D. 126
professor190 [17]

Answer:

The answer is

The measure of c is 63

5 0
2 years ago
A factory sells backpacks for $40.00 each. The cost to make 1 backpack is $10.00. In addition to the cost of making backpacks, t
Angelina_Jolie [31]

Answer:

<h2>The factory needs to sell 327 packbacks to make at least 9,800 per week.</h2>

Step-by-step explanation:

We know that each backpacks is sold for $40.00.

The goal is to make at least $9,800 per week. With this information we can define the inequality

40x -10x \leq 9,800

Where x represents backpacks. Notice that this inequality is about profits, that's why we subtract the cost from the sell price, in this case, the profid margin is $30.00 per backpack, so

30x\leq 9,800

Solving for x

x\leq \frac{9800}{30}\\ x \leq 326.67

Therefore, the factory needs to sell 327 packbacks to make at least 9,800 per week.

7 0
3 years ago
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