A hot dog vendor at a local fair averages 140 hot dogs per day when the price is $3. If for every $0.25 increase in the price, 1
0 fewer hot dogs are sold on average, what price maximizes the revenue?
$4.25
$5.75
$3.75
$3.25
1 answer:
Answer:
I think it is $3.25
Step-by-step explanation:
<u>140*3=420- </u>original price with 140 sold each day
130*3.25=422.5- 10 less hotdogs sold with $0.25 price increase
110*3.75=412.5- 30 less hotdogs sold with $0.75 price increase
90*4.25=391.5- 50 less hotdogs sold with $1.25 price increase
60*5.75=345-80 less hotdogs sold with $2.75 price increase
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Y = 2x + 6
x + y = 51...x = 51 - y
x + 2x + 6 = 51
3x = 51 - 6
3x = 45
x = 15
y = 2x + 6
y = 2(15) + 6
y = 30 + 6
y = 36
answer is : first answer choice...and ur numbers are 15 and 36
10 15 20 since i am pretty sure the rest are a triple(definitely 3 4 5 and 7 24 25 is a triple0
Answer:
x = 4 units
Step-by-step explanation:
2/z = z/6
z² = 12
z = 2√3
using the Pythagorean theorem:
x² = 12 + 2²
x² = 16
x = 4
The second one, because negative times negative equal to positive, -2(-y)= 2y
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