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3 years ago

Please help meeeee please

Mathematics

1 answer:

emmainna [20.7K]3 years ago

7 0

Answer:

14.97

Step-by-step explanation:

c^2 - a^2 = b^2

18^2 - 10^2 = x^2

324 - 100 = x^2

x^2 = 224

x = 14.97

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A public health organization reports that 40%of baby boys 6-8 months old in the United

Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

$P(X > 4) = 1 - P(X \leq 4)$

In which:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061$

$P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403$

$P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150$

$P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502$

Hence:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325$

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675$

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106$

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

$P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001$

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0

2 years ago

If a binomial event has a probability of success of 0.4, how many successes would you expect out of 6000 trials?

Feliz [49]

You should expect about 2400 successes because as a percent .4=40%

3 0

3 years ago

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Look at the figure below:

kati45 [8]

Answer:

Angle 50 and common side, in triangle MNT the sum of angles m and t is 130. In triangle PMN the sum of angles n, m is 130

Step-by-step explanation:

4 0

3 years ago

Draw one card at random from a standard deck of cards. the sample space s is the collection of the 52 cards. assume that the pro

nikklg [1K]

The probability is a ratio of the possible events to the total events. The total is 52 cards, so the denominator is 52. The individual properties of the specific cards are the following:

Any face or number cards is 4/52, because there are 4 cards for each symbol. On the other hand, each symbol like heart, diamond, club or spade would each have a probability of 13/52 (counting numbers 2 to 10, Ace card, and the 3 face cards). Also, there are 26 each of red and black cards. Furthermore, the words 'or' and 'and' are hint words. When you see 'or', you have to add their individual probabilities. If you see the word 'and', you'll have to multiply them. With that said, the solution is as follows:

a.) P = 4/52 + 4/52 + 4/52 = 3/13
b.) P = (13/52 + 13/52 + 4/52)(26/52) = 15/52
c.) P = 13/52
d.) P = 13/52 + 13/52 + 13/52 = 3/4

6 0

3 years ago

What is the answer to this 765 divided by 5

12345 [234]

765 divides by 5 = 153.

Hope that helped! :)

8 0

3 years ago

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