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DaniilM [7]
3 years ago
6

How do you do this problem

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer:


Step-by-step explanation:

sec= x

cross multiply

60 mb x 2

120 mb/29 sec

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Determine if true:<br> 9x0^1x9=9
Artemon [7]

Answer:

False

Step-by-step explanation:

9x0=0

0^1=0

0x9=0

0=9

The numbers don't match.

Hence, the equation is false.

5 0
2 years ago
Read 2 more answers
Simplify the expression.<br> (the quantity x to the one-sixth power end quantity to the power of 3.)
Usimov [2.4K]

Answer:

\sqrt{x}

Step-by-step explanation:

If we have that worded expression, we can convert it into actual mathematical terms.

x to the one sixth power: x^{\frac{1}{6}}

That to the power of 3:

(x^{\frac{1}{6}})^3

Using exponent rules, since we have a power to a power, the powers multiply, so:

x^{\frac{1}{6}\cdot 3}\\\\x^{\frac{3}{6}}\\\\ x^{\frac{1}{2}}

If we have a number to a fraction power, the denominator becomes the “find the (denominator) root of x.

So:

x^{\frac{1}{2}} = \sqrt{x}

Hope this helped!

8 0
2 years ago
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416/8 long division
Ganezh [65]
The answer for that question is 52
3 0
3 years ago
Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression
Brut [27]

The area of rectangle with length l and width w is

A=l\cdot w.

If the length of rectangle is expressed as l=3x^2 + 5x + 10 and the width of rectangle is expressed as w=x^2-3x-1, then the area of rectangle is

A=(3x^2 + 5x + 10)(x^2-3x-1)=3x^4-4x^3-8x^2-35x-10.

8 0
3 years ago
Read 2 more answers
How do I solve this?
andreev551 [17]

Answer:

x is in the range [-1,4]

Step-by-step explanation:

I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.

We are given the following inequality:

| 2x - 3 | <= 5

This implies two possible cases:

[1] -5 <= 2x -3

Or

[2] 2x - 3 <= 5

So let's solve x for both of these cases:

[1] -5 <= 2x - 3

 -2 <= 2x

 -1  <= x

[2]  2x - 3 <= 5

 2x <= 8

  x <= 4

So from these cases, we can say the following is true:

x >= -1  and x <= 4

Thus, we can write this in the form

-1 <= x <= 4

Or in interval notation:

{ x is element of reals | -1 <= x <= 4}

Also written as

x is in the range [-1,4]

Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.

Cheers.

4 0
3 years ago
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