Which quadraric equation has roots -2 and 3
1 answer:
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If , then by rationalizing the denominator we can rewrite
Now,
and
Answer:
B
Step-by-step explanation:
This was originally a third degree polynomial:
, to be exact.
When you divide by -3, you are basically trying to determine if x + 3 is a zero of that third degree polynomial. The quotient is always one degree lesser than the polynomial you started with, and if there is no remainder, then x + 3 is a zero of the polynomial and you could go on to factor the second degree polynoial completely to get all 3 solutions. To perform the synthetic division, you always first bring down the number in the first position, in our case a 2. Then multiply that 2 by -3 to get -6.
-3| 2 4 -4 6
-6
2 -2
So far this is what we have done. Now we multiply the -3 by the -2 and put that up under the -4 and add:
-3| 2 4 -4 6
-6 6
2 -2 2
Now we multiply the -3 by the 2 to get -6 and put that up under the 6 and add:
-3| 2 4 -4 6
-6 6 -6
2 -2 2 0
That last row gives us the depressed polynomial, which as stated earlier here, is one degree less than what you started with: