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ahrayia [7]
2 years ago
12

Wich one doesn't belong

Mathematics
1 answer:
Artist 52 [7]2 years ago
7 0

Answer:

The answer is 3 because its a constant value and the rest are variables

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Please help, i can't figure this out and im ready to pull my hair out!!!
Nat2105 [25]

Answer:

I'm sorry I don't know the equation, but she walks 3 mph.

Step-by-step explanation:

We know that the answer is asking for speed, which needs both distance and time, so we also need both. Which is where the 9 mph is used. 9 mph means its a difference. b means biking mph, w means walking mph, sooo ----->>> b=w+9, and the difference in the 1st equation is 36, which means the first equation is 4 times larger than the b=w+9, so she walked 48 miles, as well as walked 12 miles in 4 hours. Divide then distances by 4, and you get 12 miles and 3 miles in one hour. Or 12 mph & 3 mph, which fits into 12=3+9. So she walks 3 miles per hour.

5 0
2 years ago
A ship goes at the rate of (3m-2) knots per hour. How far can it travel in (4m+9) hours?
Ber [7]

Answer: 12m^2+19m-18

Step-by-step explanation:

Given

Speed of boat v=3m-2\ \text{knots per hour}

\text{time t= }4m+9\ \text{hours}

\Rightarrow \text{Distance =speed}\times \text{time}

\Rightarrow \text{Distance d=}(3m-2)\cdot (4m+9)\\\Rightarrow d=12m^2+19m-18

7 0
3 years ago
Find the value of d such that the system of equations
vova2212 [387]

Answer:

18x okkklllkkkkkkkkkkkkkkkkkkkkkkkkkkmmm

4 0
3 years ago
A car travels 58.8 kilometers in 2.6 hours. What is the car's average speed?
NISA [10]

Answer:

22.6 km/hr

Step-by-step explanation:

58.8/2.6=22.6

7 0
2 years ago
Read 2 more answers
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto P
Dmitriy789 [7]

Answer:

Step-by-step explanation:

Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB

=> MP là đường trung bình của tam giác DAB => MP//BD và MP=\frac{1}{2}BD  (1)

Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC

=> QN là đường trung bình của tam giác DBC => QN//BD và QN=\frac{1}{2}BD  (2)

Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN

và độ dài MP = độ dài QN = \frac{1}{2}BD

=> vecto MP = vecto QN

Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN

4 0
2 years ago
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