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4 years ago

Points C, A, and B are collinear. Which of the following options is another name for CA ?

Mathematics

2 answers:

Flauer [41]4 years ago

3 0

AC

Same line segment just goes in the other direction.

Amanda [17]4 years ago

3 0

Three or more points are said to be collinear points when these all points lie on the single straight line.

Since, it is given that the points C,A and B are collinear, it means that the points C,A and B lie on the single straight line. We have to identify the another name for CA.

Since the same line segment just goes in the same direction. Therefore, AC is the another name for the line segment CA.

So, Option 1 is the correct answer.

You might be interested in

Which function represents a reflection of f(x) = Three-eighths(4)x across the y-axis? g(x) = NegativeThree-eighths (one-fourth)

nignag [31]

The function which represents a reflection of f(x) is

g(x) = Three-eighths $(4)^{-x}$ ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the axes

If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ Three-eighths = $\frac{3}{8}$

∴ $f(x)=\frac{3}{8}(4)^{x}$

∵ f(x) is reflected across the y-axis

- That means the sign of x coordinates of the points on the graph will

change to opposite

∴ x will change to -x

∴ $g(x)=\frac{3}{8}(4)^{-x}$

The function which represents a reflection of f(x) is

g(x) = Three-eighths $(4)^{-x}$

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

9 0

3 years ago

Read 2 more answers

L M A O L M A O L M A O L M A O

kiruha [24]

Not sure if this is a question im confused

6 0

3 years ago

Read 2 more answers

PLease help!!

weqwewe [10]

√45 + √125

= 3√5 + 5√5

= 8√5

Answer is C.

Hope it helps!

6 0

3 years ago

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r

SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable X that follows a Binomial distribution with parameters, sample size n and probability of success p.

It is provided that the distribution of proportion of random variable X, $\hat p$ , can be approximated by the Normal distribution.

The mean of the distribution of proportion is, $\mu_{\hat p}=\hat p$

The standard deviation of the distribution of proportion is, $\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$ .

Then the confidence interval for the population proportion p is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The confidence level is 99%.

The significance level is:

$\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01$

Compute the critical value as follows:

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}$

That is:

$P(Z>z)=0.005\\P(Z$

Use the z-table for the z-value.

For z = 2.58 the P (Z < z) = 0.995.

And for z = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0

4 years ago

Need help fast please

dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4

14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0

15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x

16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10

8 0

4 years ago