F(g(x)) = x + 1 . Just replace square root of x-2 to x in f(x)
The solution to these linear equations is (4,-3)
So the x-value is 4
:)))
21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
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No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
What are you looking for? Please ensure that you have copied down the complete original question.
If, for example, the usual price of the cycle is $4,100, and we want to know how much one could save by buying the cycle at $3,600, we must subtract $3,600 from $4,100:
$4,100
- 3,600
-----------
$500
Answer:
Step-by-step explanation: