10(1+3x)=-20 and -5x-8(1+7x)=-8
With steps
1 answer:
(1)
10(1+3x)=-20
Cross multiply.
10+30x=-20
Isolate x on one side. So you would subtract 10 on each side. and one side will cross each other out. leaving you with,
30x=-20-10
Subtract 10 from -20.
30x=-30
Divide each side by 30 to get x.
30x÷30=-30÷30
Therefore,
x=-1
(2)
-5x-8(1+7x)=-8
Cross multiply -8(1+7x)
-5x-8-56x=-8
Isolate all x's on one side. So you would add 8 on each side. and one side will cross each other out. leaving you with,
-5x-56x=-8+8
Add 8 to -8.
-5x-56x=0
Subtract -56x from -5x
-61x=0
Divide each side by -61
-61x÷-61=0÷-61
Therefore,
x=0
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2/5 * (n - 1) < 3/5 * (n + 1)
2/5 * n - 2/5 < 3/5 * n + 3/5
- 2/5 - 3/5 < 3/5 * n - 2/5 * n
- 5/5 < 1/5 * n
- 1 < 1/5 * n /*5
- 5 < n
n > - 5
n = x
The correct result would be B) <span>x > - 5.</span>
D the rest would be impossible to recreate
Hope This Helps
#1: "AD" is congruent to "BC" | given
Simply remember PEMDAS:
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
You perform these actions from left to right.
However in this case it is not possible for it to equal 60.
The LCM is 540 because 54X10=540 which 20 goes into
