Find the equation of the line parallel to y=2x+1 that contains point (14,3)
1 answer:
First of all, remember what the equation of a line is:
Where:
m=slope
b=y-intercept.
Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope
Because we were given the point (14,3)
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We need to find the value of b. The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).
<span>Plug in for x the number 14 and for y the number 3:</span>(14,3).
y=mx+b or 3=2 × 14+b,
solving for b: b=3-(2)(14). b=-25.<span>Plug that in for b:
</span><span>y=2x-25
<span>Final answer:
</span><span>y=2x-25</span></span><span><span>
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Okay, take a look at diagram 1 (I know it's rubbish I did it on paint :D), this shows all the information you've given in the question. The two coordinates and the distance between them.
Now if we draw additional lines on this diagram, we can make a right-angled triangle (this is on diagram 2). We can also work out the lengths of the additional sides because we know both coordinates at the end-points of the additional lines.
Finally because this is a right-angled triangle, Pythagoras' theorem must apply to its sides meaning
therefore x=5.
Now if we draw additional lines on this diagram, we can make a right-angled triangle (this is on diagram 2). We can also work out the lengths of the additional sides because we know both coordinates at the end-points of the additional lines.
Finally because this is a right-angled triangle, Pythagoras' theorem must apply to its sides meaning
therefore x=5.