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marusya05 [52]
3 years ago
11

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, a

nd a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?
A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).
Mathematics
2 answers:
densk [106]3 years ago
6 0
The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then <span>C.) The graph of the function is positive on (–2, 4).</span>
siniylev [52]3 years ago
4 0

Answer:

C -2,4

Step-by-step explanation:

i got it right on edge

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Answer:

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Step-by-step explanation:

For this case we know that the french fries cost $0.50 and we want to have a margin of 75% on the fries. So we can use the following proportional rule:

\frac{0.5}{100} = \frac{x}{175}

0.5 represent the original 100% but we want to obtain a 75% aditional so we can find for the value x if interest and we got:

x= 175 *\frac{0.5}{100} =0.875

So we need to sell the fries ar 0.875$ if we want to obtain a 75% of margin

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