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marusya05 [52]
3 years ago
11

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, a

nd a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?
A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).
Mathematics
2 answers:
densk [106]3 years ago
6 0
The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then <span>C.) The graph of the function is positive on (–2, 4).</span>
siniylev [52]3 years ago
4 0

Answer:

C -2,4

Step-by-step explanation:

i got it right on edge

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4/r=5/7solve for r. Help pls
antiseptic1488 [7]
Hello!

You first cross multiply

4 * 7 = 28

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Hope this helps!
4 0
3 years ago
Read 2 more answers
HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c
Anna71 [15]

Answer:

n=241

Step-by-step explanation:

We are given

5x^2+nx+48

Let's assume it can be factored as

5x^2+nx+48=(5x-s)(x-r)

now, we can multiply right side

and then we can compare it

5x^2+nx+48=5x^2-5rx-sx+rs

5x^2+nx+48=5x^2-(5r+s)x+rs

now, we can compare coefficients

rs=48

5r+s=-n

n=-(5r+s)

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

48=-+(1\times 48)

48=-+(2\times 24)

48=-+(3\times 16)

48=-+(4\times 12)

48=-+(6\times 8)

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

n=-(5\times -48-1)

n=241


7 0
3 years ago
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