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Zina [86]
3 years ago
14

From 1985 to 2007, the number B B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 B(t)=-329.4t+1

3747 where t is the year and t=0 corresponds to 1985. How many federally insured banks were there in 1990?
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

12100

Step-by-step explanation:

If the number B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 from 1985 to 2007 where t = 0 correspond to year 1985

In order to determine the amount of federally insured banks that were there in 1990, we will first calculate the year range from initial time 1985 till 1990

The amount of time during this period is 5years. Substituting t = 5 into the modeled equation will give;

B ( t ) = − 329.4 t + 13747

B(5) = -329.4(5) + 13747

B(5) = -1647+13747

B(5) = 12100

This shows that there will be 12100 federally insured banks are there in the year 1990.

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21 = − 6 x − 3 x + 4 + 4 x
horsena [70]

Answer:

x=-17/5

Step-by-step explanation:

1. Simplify  -6x-3x+4+4x−6x−3x+4+4x  to  -5x+4−5x+4.

21=−5x+4

2. Subtract 44 from both sides.

21−4=−5x

3. Simplify  21-4 to 17.

17=-5x

4. Divided both sides by -5.

-17/5=x

5. Switch sides.

x=-17/5

Hope this helps.

4 0
3 years ago
Which expression should you simplify to find the 90% confidence interval,
Alex787 [66]

Answer:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287

0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is \hat p=0.45

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value is:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the true population proportion is interest is given by this formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the values provided we got:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287

0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

8 0
2 years ago
Two similar triangles are shown below which two sets of angles are corresponding angles p and q
Oduvanchick [21]

Answer:   p = 30  q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120  and p and q = 30

Step 1)  Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides =  (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree   Where the measure of each angle of a hexagon = 720/ 6 = 120 degree   Step 2) Then show 3 angle letter names = 180 degree     Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree    Step 3) State since triangle name (of all letters within one triangle) is Isosceles   Step 4) <u>Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60  then state triangle (letter name) / 2 = 30 degrees </u>obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon =  (3 *180) / 5 = 108  then due to isosceles (180 - 108)/ 2  = 72/2 = 36 degree for a p<u>entagon </u>or 30 degree each for p + q for a <u>hexagon</u> etc

6 0
2 years ago
480 = 3,000 x R x 2. What is R?
7nadin3 [17]

Answer:

R= 0.08 i think

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The Badgers and the Cougars have won the same number of games. However, the Badgers have won a greater percent of their games th
pogonyaev

Answer: This is possible because of the total of matches played. If the Badgers have won a greater percentage of their games than the Cougars, it means that they played less games.

Step-by-step explanation: The percentage of games won is related to the total number of games played. For example, let's suppose that the Badgers played 10 games, won 6 and lost 4, they won 60% of their games. If the Cougars played 12 games, won 6 and lost 6, their percentage is 50%. This way, they have the same number of wins but different percentages.

8 0
3 years ago
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