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Scorpion4ik [409]
3 years ago
6

anonymous 2 years ago If you were to solve the following system by substitution, what would be the best variable to solve for an

d from what equation? 2x+6y=9 3x-12y=15 A.y, in the second equation B.x, in the first equation C.y, in the first equation D.x, in the second equation Calculus1
Mathematics
1 answer:
Ainat [17]3 years ago
7 0
I'm sorry that I'm not in calculus, but hopefully I can help.
Personally, I would choose: D.) x; in the second equation ;
because it has easier numbers to figure out, you'll get it eventually...
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Pls need help w this question
zhuklara [117]
Ok here me out.... 25
4 0
3 years ago
In​ 2012, a health insurance plan for a​ 35-year-old and his or her spouse costs ​$301 per month. That rate increased to ​$430 p
katrin2010 [14]

Answer: See explanation

Step-by-step explanation:

Let the cost for insuring the applicant = a.

Let the cost for insuring the spouse = b

Let the cost for insuring the first child= c

Let the cost for insuring the second child = d

A 35-year-old health insurance plan and that of his or her spouse costs ​$301 per month. This means that:

a + b = $301.

That rate increased to ​$430 per month if a child were included. This means the cost of a child will be:

= $430 - $301

= $129

The rate increased to $538 per month if two children were included. This means the cost for the second child will be:

= $538 - $430

= $108

The rate dropped to ​$269 per month for just the applicant and one child. His will be the cost of the applicant and a single child. This can be written as:

a + $129 = $269

a = $269 - $129

a = $140

Since a + b = $301

$140 + b = $301

b = $301 - $140

b = $161

Applicant = $140

The spouse = $161

The first​ child = $129

The second child = $108

3 0
3 years ago
5h+3 - j; use h = 6, and j = 1
olga55 [171]

Answer:

32

Step-by-step explanation:

lets substitute the appropriate values in the equation:

5h+3 - j    h= 6    j=1 , so we have:

5*6 +3 -1

30 +3 -1

32

7 0
3 years ago
Read 2 more answers
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nexus9112 [7]

Answer:

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Step-by-step explanation:

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3 years ago
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A unit of astronomical distance equivalent to the distance that light travels in one year, which is 9.4607 times 1012<span> km nearly 6 trillion miles.</span>
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3 years ago
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