<span>The expression of the square root of 19x must be simplified when x is equal to 28. This is because possible factors of 28 can be seen to be 4 and 7, and 4 is a perfect square. This means it can be pulled outside of the square root when evaluated. The other options include only prime factors that could not be pulled out. (3,5), (3,7), (1,41)
28 simplifies as such:
Sqrt(19*28) = Sqrt(19*4*7) = 2*Sqrt(19*7) = 2*Sqrt(133).</span>
Answer:
1. Identify the problem: Packaging boxes use too much material and create waste
2. What are the equations for the volume and surface area of a cube and rectangular prism?
Volume of a cube: Vcube = L x L x L = L3
Surface area of a cube: SAcube = 6 x (L x L) = 6L2
Volume of a rectangular prism: VRP = L x W x H = LWH
Surface area of a rectangular prism: SARP = 2 x (L x W) + 2 x (L x H) + 2 x (W x H) = 2(LW + LH + WH)
3. What is the difference in surface area of the packages below? (Note that they have the same volume.)
SAcube = 6L2
= 6 (20 cm)2
= 2,400 cm2
SARP = 2(LW + LH + WH) = 2 (20cm x 10cm + 20cm x 40cm + 10cm x 40cm) = 2,800 cm2
SARP – SAcube = 2,800 cm2
– 2,400cm2
= 400 cm
Step-by-step explanation:
everything in bold is the answer
Can I please get the Brainlist
Answer:
200 US DOLLARS
Step-by-step explanation:
Given; $1=R17
To find: How much is Zar3400 in US DOLLARS
$1=R17
R3400=3400/17 US DOLLARS
=200 US DOLLARS
Hope my answer is right thank you.
Answer: hypotenuse = 
Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (
) of the right triangle, .i.e.:

In this question:
= 
2bc
Substituing and taking square root to find hypotenuse:

Calculating:


=
, then:


Hypotenuse for the right-angled triangle is
units
Answer:
2
Step-by-step explanation:
There are two lines of symmetry and here I list them:
1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).
2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.
A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.
So, we only have 2 symmetry lines.