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Marysya12 [62]
3 years ago
11

Trigonometry Special Right Triangles Find the exact value of tan 0* + cos 90* - sin 0*.

Mathematics
1 answer:
Margarita [4]3 years ago
6 0

Answer:

0

Step-by-step explanation:

tan(0) = 0

cos(90) = 0

sin(0) = 0

0 + 0 - 0 = 0

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Please help me. <br><br><br>2 (a + 4) =
vitfil [10]

Answer:

2a+8

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
I hope you guys can see the question, if not just let me know
QveST [7]

Answer:

The correct answer is 6.

Step-by-step explanation:

When translating and reflecting figures, the shape remains the same. So, the side of 2x-4 is corresponding to the side of 8 and they are equal to each other.

To solve, set up an equation like this to find x:

2x-4=8

Then, add 4 to both sides of the equation:

2x=12

The goal is to get x by itself and in order to do that, divide both sides by 2:

x=6

The value of x is 6. I hope this helps! ☺

3 0
3 years ago
What is 250.6 rounded to the nearest hundredth?
musickatia [10]
250.6 is your number

The "6" in .6 right after the decimal is the tenths place

So right after the tenths place is the hundredths place

But as you can see in 250.6, there is no hundredths place you can see so it is 0

250.60 is the same as 250.6

So 250.6 is already rounded to the nearest hundredths
3 0
3 years ago
43 = 20 + z/3 please help
BabaBlast [244]

Answer:

z = 69

Step-by-step explanation:

43 - 20 = z/ 3

23 = \frac{z}{3}

cross multiply

z = 23 x 3

z =69

3 0
3 years ago
Trigonometry pile up. Anyone mind helping me out with this one?
S_A_V [24]
cos34^o=\frac{8}{a};\ cos34^o\approx0.829\\\\\frac{8}{a}=0.829\to a\approx9.65\\\\9.65-2.5+3.6=10.75\\\\cos11^o=\frac{b}{10.75};\ cos11^o\approx0.981\\\\\frac{b}{10.75}=0.981\to b\approx10.55\\\\10.55-2.1+2.9=11.35\\\\c^2+3.8^2=11.35^2\\\\c^2=11.35^2-3.8^2\\\\c\approx10.69

10.69-3.2=7.49\\\\tan42^o=\frac{d}{7.49};\ tan42^o\approx0.9\\\\\frac{d}{7.49}=0.9\to d\approx6.74\\\\sin37^o=\frac{6.74}{e};\ sin37^o\approx0.602\\\\\frac{6.74}{e}=0.602\to e\approx11.2\\\\11.2+4.3=15.5\\\\sin53^o=\frac{f}{15.5};\ sin53^o\approx0.8\\\\\frac{f}{15.5}=0.8\to f\approx12.4

12.4-2.2=10.2\\\\g^2=10.2^2+1.7^2\to g\approx10.34\\\\cos21^o=\frac{10.34}{h};\ cos21^o\approx0.934\\\\\frac{10.34}{h}=0.934\to h=11.07\\\\11.07+1.7=12.77\\\\sin71^o=\frac{x}{12.77};\ sin71^o\approx0.946\\\\\frac{x}{12.77}=0.946\to x\approx12.1\ (cm)\leftarrow Answer

4 0
3 years ago
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