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givi [52]
3 years ago
13

Is 81 divisible by 3?

Mathematics
2 answers:
kompoz [17]3 years ago
4 0
Add up the digits that make 81 as follows: 8 + 1 = 9

We know that if the sum of the numbers that make up 81 is divisible by 3, then 81 is divisible by 3.

<span>Since the sum of the digits in 81 is divisible by 3, 81 is also divisible by 3. Thus, the answer to the question "Is 81 divisible by 3?" is as follows: </span>

<span>Yes</span>
AlexFokin [52]3 years ago
3 0
Yes 81 is divisible by 3
the answer is 27
because 81 divided by 3 = 27

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SOMEONE PLEASE HELP IF U GET IT RIGHT ILL GIVE U 15 POINTS PLEASE
Novosadov [1.4K]

Answer:

There is no solution, y-int of one line is positive

Step-by-step explanation:

There is no solution because there are no shared points between both lines, and the y intercept of the blue line is positive, because it is above the x-axis.

7 0
3 years ago
6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at
SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

\frac{dQ}{dt}= flow\ in - flow\ out\\ \\flow\ in=3\ gal/min*2\ lb/gal=6\ lb/min\\\\net\ gain\ in\ tank\ volume=3-4=-1, henceflow\ out= \frac{4Q}{100-t} \\\\\frac{dQ}{dt}= 6-\frac{4Q}{100-t} \\\\\frac{dQ}{dt}+ \frac{4Q}{100-t}=6\\\\The \ integrating\ factor\ is:\\\\IF=e^{\int\limits {\frac{4}{100-t} } \, dt }=e^{-4\int\limits {\frac{-1}{100-t}}=e^{-4ln(100-t)}=(100-t)^{-4}}\\\\Multiplying\ through  \ by\ IF: \\\\(100-t)^{-4}\frac{dQ}{dt}+ (100-t)^{-4}\frac{4Q}{100-t}=6(100-t)^{-4}\\\\

Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}

7 0
3 years ago
The ratio of marbles to stones is 5 to 7 if there are 35 marbles how many stones is there?
icang [17]
5 : 7
Marbles : Stones

35/5 = 7
So stones
= 7 * 7
49

=35 : 49
3 0
3 years ago
Read 2 more answers
PLEASE HURRY 50 POINTS Answer Both parts and I will reward Brainliest
vlabodo [156]

We have:

a_1=-3

and:

r=4

so:

$\sum\limits_{n=2}^5\,-3\cdot4^{n-1}=\sum\limits_{n=1}^5\,-3\cdot4^{n-1}-a_1=S_5-a_1=\frac{-3-(-3)\cdot 4^5}{1-4}-(-3)=

=\dfrac{-3-(-3)\cdot 1024}{-3}+3=\dfrac{-3(1-1024)}{-3}+3=1-1024+3=\boxed{-1020}

It is a finite sum, so it is convergent.

6 0
3 years ago
Select all that apply.
vfiekz [6]

Answer:

1/3 , 4/15 , 5/6

Step-by-step explanation:

All you have to do is plug the fractions in your calculator and you see that 1/3, 4/15, and 5/6 are repeating, but the others stop after only a couple of decimal places.

Hope this helps!

4 0
3 years ago
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