Answer:
Okay So I see you need to change 1/3 to a denominator of 6
You don't do anything to the -1/6
But to change the 1/3 you need to multiply 3 and 1 by two, which is 2/6
And the -1/6 stays the same
Answer:
D
Step-by-step explanation:
Answer:
6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- |Absolute Value| - makes any number positive
Step-by-step explanation:
<u>Step 1: Define</u>
|bc|
a = 5
b = -3
c = -2
<u>Step 2: Evaluate</u>
- Substitute: |-3 · -2|
- Multiply: |6|
- Evaluate: 6
0 = f(x) = (x - r)(x - s) = x² - (r+s) + rs
We have r=1.5+√2, s=1.5 -√2 so r+s = 3 and
rs = (1.5+√2)(1.5 - √2) = 1.5² - (√2)² = 2.25 - 2 = 0.25
f(x) = x² - 3x + -.25
For integer coefficients we mulitply by 4,
g(x) = 4f(x) = 4x² - 12x - 1
Answer: 4x² - 12x - 1 = 0
5. 60/12 is 5 :) hope this helps