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Sedaia [141]
3 years ago
5

Find BC. Please and thank you

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0
X = 9, so line BC = 25
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Solve this problem to find Y. 800 x Y = 4800
kupik [55]

Answer:

6

Step-by-step explanation:

800*Y=4800

Y=4800/800

Y=6

5 0
3 years ago
Read 2 more answers
A frozen pizza is on sale at a 25% discount. Find the sales price of the pizzas if it normally sells for $4.85.
bonufazy [111]
The best thing to do here is to divide $4.85 by 10, and then multiply it by 2.5. $4.85/10= $0.48. $0.48x2.5= $1.20 Therefore,the discount is $1.20, you've then got to subtract this from $4.85. $4.85-$1.20= $3.65 $3.65 is the sale price of the pizza. Hope this helps :)
4 0
3 years ago
A first number is nine less than a second. The sum of the numbers is 45. Find the numbers.
oee [108]

Answer:

The first number is <u>18</u> and the second number is <u>27</u>.

Step-by-step explanation:

Given:

A first number is nine less than a second.

The sum of the numbers is 45.

Now, to find the numbers.

Let the second number be x.

And the first number be x-9.

The sum of the both numbers is 45.

According to question:

(x-9)+x=45.

⇒ x-9+x=45.

⇒ 2x-9=45.

<em>Adding both sides by 9 we get:</em>

⇒ 2x=54.

<em>Dividing both sides by 2 we get:</em>

⇒ x=27.

<u><em>The second number = 27</em></u>.

Now, to get the first number we put the value of x:

x-9

=27-9

=18.

Therefore, the first number is 18 and the second number is 27.

4 0
3 years ago
What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f
ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

6 0
3 years ago
Please help me <br>by the way this is a 2 mark question from mathswatch​
BigorU [14]

Answer:

y = - 13, y = 13

Step-by-step explanation:

Given

y² = 169 ( take the square root of both sides )

y = ± \sqrt{169} = ± 13

Since 13 × 13 = 169 and - 13 × - 13 = 169

3 0
3 years ago
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