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3 years ago

Which of the following numbers is a multiple of 6?

2 answers:

7 0

6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
6x9=54
6x10=60
6x11=66
6x12=72
6x13=78
6x14=84
6x15=90
6x16=96
6x17=102
6x18=108
6x19=114
6x20=120
6x21=126
6x22=132
6x23=138
6x24=144
6x25=150
6x26=156

that is all the multiples of 6 up to 6x26 hope it helps :)

LiRa [457]3 years ago

4 0

<span>The multiples of 6. Answer : 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,1</span>

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Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were:

Sunny_sXe [5.5K]

Answer:

Option B.

Step-by-step explanation:

The given data set is

34, 35, 41, 28, 26, 29, 32, 36, 38, 40

We need to find the mean deviation of the given data.

Number of observations, n = 10

Mean of the data is

$Mean=\dfrac{\sum x}{n}$

$Mean=\dfrac{34+35+41+28+26+29+32+36+38+40}{10}$

$Mean=\dfrac{339}{10}$

$Mean=33.9$

Formula for mean deviation is

$\text{Mean deviation}=\dfrac{\sum |x-mean|}{n}$

$\sum |x-mean|=|34-33.9|+|35-33.9|+|41-33.9|+|28-33.9|+|26-33.9|+|29-33.9|+ |32-33.9|+|36-33.9|+|38-33.9|+|40-33.9|=41.2$

$\text{Mean deviation}=\dfrac{41.2}{10}$

$\text{Mean deviation}=4.12$

The mean deviation of the ratings is 4.12.

Therefore, the correct option is B.

8 0

3 years ago

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icang [17]

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(Hope this helps)

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Answer:

It's 90 because we'll make it equal

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Is a rise of -7 the same as a fall of 7

iVinArrow [24]

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A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m, to the nearest tenths place?

Ronch [10]

<h3>Answer:</h3>

301.6 cubic meters

<h3>Step-by-step explanation:</h3>

A cylinder is a shape with straight sides with circular or oval cross-sections. We know that the cylinder in the question must be a circular cylinder due to its radius description.

Volume Formula

A circular cylinder has a volume of $V=\pi r^2h$ . In this equation, V is the volume, r is the radius, and h is the height. The question tells us that r=4m and h=6m. So, we can plug these values into the formula.