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3 years ago

13

Find the rectangle of largest area that can be inscribed in a semicircle of radius r, assuming that one side of the rectangle li

es on the diameter of the semicircle.

1 answer:

cestrela7 [59]3 years ago

3 0

The two below rectangle shows the inscribed rectangle and diameter that lies on the circle.

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Find y when x is -3<br> y=6x+8

lys-0071 [83]

Answer:

-10

Step-by-step explanation:

y=6x+8

y=6(-3)+8

y=-18+8

y=-10

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3 years ago

A snowstorm lasted for three days. During the storm, 8 inches of snow fell on the first day, 6 inches of snow fell on the second

PIT_PIT [208]

Answer:

Step-by-step explanation:

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3 years ago

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

sveta [45]

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x) = f(x) - g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

$= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS, we get

f(x) - g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

4 0

3 years ago

Which equation represents the polar form of x² + (y + 4)² = 16?

Paraphin [41]

$x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )$

3 0

2 years ago

Question is below in picture

Ivan

It's $x^{2} +6x+1
/x(x+2)$ because this choice made the most since.

4 0

3 years ago