Answer:
y = 3x + 3
Step-by-step explanation:
First, you check for the y-intercept, which is 3 for this equation.
In order to find the slope, pick two points and apply the slope formula.
I would just use rise/run. The slope should be 3/1.
Answer:d
its a apartment thats just one big room
For the answer to the question above asking to p<span>rove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle,
</span>A right triangle consists of two sides called the legs and one side called the hypotenuse (c²) . The hypotenuse (c²)<span> is the longest side and is opposite the right angle.
</span>⇒ α² + β² = c²
<span>
"</span>In any right triangle ( 90° angle) <span>, the sum of the squared lengths of the two legs is equal to the squared length of the hypotenuse."
</span>
For example: Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are 3 inches and 4 inches.
c2 = a2+ b2
c2 = 32+ 42
c2 = 9+16
c2 = 15
c = sqrt25
c=5
Answer:
x = 4
Step-by-step explanation:
ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same
We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 :
: 2
2
/RT =
/2
cross-multiply:
· RT = 4
RT = 4
Therefore, x = 4
The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
brainly.com/question/15602982
#SPJ1