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Anarel [89]
3 years ago
14

Sara went out for lunch with a group of 25 friends. Each person purchased either a sandwich for $4.00 or a bowl of soup for $3.5

0, tax included. The bill came to $94.00. How many people purchased a bowl of soup?
A) 12
B) 6
C) -136
D) 20
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0
The answer would be A)12
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In the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
Vanyuwa [196]
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
7 0
3 years ago
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I will give brainliest if you answer all correctly ​
miskamm [114]

Answer:

I think 13 is C

Step-by-step explanation:

71+52= 123

180-123= 57

7 0
3 years ago
HOW DO I DO NUMBER 7?!?? WHATS THE ANSWER?!?!??????
hichkok12 [17]
Simple actually. The 1000 is the starting price the -20 is the losing of value per week and the w stands for the number of weeks.
5 0
3 years ago
Here are 100 seats on an airplane, and each of 100 passengers has a ticket for a different seat. The passengers line up to board
Kryger [21]

Answer:

There are 1% probability that the last person gets to sit in their assigned seat

Step-by-step explanation:

The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.

If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.

LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!

Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.

P = 99!/100! = 99!/ (100 * 99!) = 1/100

There are 1% probability that the last person gets to sit in their assigned seat

7 0
3 years ago
Someone please help me will give BRAILIEST!!!!!!
rewona [7]
The answer is true plz thnk me
4 0
3 years ago
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