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3 years ago

Solve the exponential equation use a calculator to obtain a decimal approximation correct to two decimal place for the solution.

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

6^(8x) = 4
log 6^(8x) = log 4
8x log 6 = log 4
x = log 4 / 8log 6 = 0.10 to two decimal places.

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Peter is writing a number in scientific notation.The number is grater that ten million and less that one hundred million.Which e

OLga [1]

Answer:

$M = a \times 10^7$ where 1 < a ≤ 9

The EXPONENT USED BY PETER is 7 in all the possible cases.

Step-by-step explanation:

Let us assume the needed number is M.

Also, given:

The needed number is GREATER than 10 Million.

⇒ M > 10 Million

⇒ M > 10,000,000

⇒ M > $1 \times 10^7$ ...... (1)

The needed number is SMALLER than 100 Million.

⇒ M < 100 Million

⇒ M < 100,000,000

⇒ M < $1 \times 10^8$ ...... (2)

Comparing (1) and (2) we can see that M can have more than 7 zeroes after 1 but LESS than 8 zeroes after 1.

So, the possible values of M can be:

$M = a \times 10^7$ where 1 < a ≤ 9

So, the EXPONENT USED BY PETER is 7 in all the possible cases.

5 0

4 years ago

A math book comprises of 2 sections: arithmetic and geometry in the ratio 5:3. How much of each type of content will be needed t

Alex_Xolod [135]

480/8=60

(60*5) : (60*3) = 300:180

4 0

3 years ago

Read 2 more answers

What is the degree of x4 - 3x + 2?

sukhopar [10]

Answer:

Step-by-step explanation:

Since the highest power of x is 4 in this case.

8 0

4 years ago

A hot air balloon rising vertically is tracked by an observer located 5 miles from the lift-off point. At a certain moment, the

Zigmanuir [339]

Answer:

Step-by-step explanation:

aThe person and the hot air balloon form a right triangle, with the lift-off point as the vertex that form the right angle. If you were to try to solve for the height of the balloon, you would need to use tangent to do so:

tanθ = opp/adj = y/x

y = xtanθ

What this problem ultimately wants to know, is how the distance of the balloon is changing with respect to time: dy/dt. So we need to take the derivative of the above equation (you need to product rule to do so):

dy/dt = (dx/dt)tanθ + xsec2θ(dθ/dt)

We need to find out values for all of the variables:

The observer is not moving, therefore dx/dt = 0.

The observer is standing 4 miles away from the lift-off point, so x = 4.

The angle between the horizontal and the observer's line of sight is π/3, therefore θ = π/3.

The rate of change for the angle, dθ/dt, is 0.1.

Just plug all the numbers in:

dy/dt = (0)tan(π/3) + (4)sec2(π/3)(0.1)

dy/dt = 0 + 1.6

dy/dt = 1.6 mi/min

5 0

2 years ago