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notka56 [123]
3 years ago
15

Jerry was comparing the points the bulls socered for different games he recorded 85,85, 86,77, 93 determine the mean median mode

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0
Answers:
Mean - 85.2
Median - 85
Mode - 85

Explanation:
Mean - 77+85+85+86+93=426/5 (the amount of data points given) = 85.2

Median - Organize the data points from least to greatest and eliminate the outermost numbers two at a time (one from both side) until you’re left with one.

Mode - The number that appears the most often in a given data set
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Please help-help-help
disa [49]
I think the answer is C
3 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
(3,6) (3,7) (-2,-5) (-9,11) is it a function a relation, or both
amid [387]

It is a relation but not a function

Step-by-step explanation:

Given

(3,6) (3,7) (-2,-5) (-9,11)

First of all we have to define both terms: Relation and Function

A relation is a set of ordered pairs containing one element from each set

A relation can be a function only if there is no repetition in domain i.e. no first element in each ordered pair should be repeated.

In the given set of ordered pairs, they are relation as all the ordered pairs have two values.

While the given relation is not a function, as there is repetition in first elements of two ordered pairs i.e. 3 is repeated in (3,6) (3,7)

Hence,

It is a relation but not a function

Keywords: Functions, Relations

Learn more about functions at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

6 0
3 years ago
Factor 2x^2 + 7x + 3
Vlad1618 [11]

Answer: (x - 3) (2x-1)

8 0
3 years ago
Read 2 more answers
You roll a 6-sided die. What is P(factor of 10)? Write your answer as a percentage rounded to the nearest tenth.
exis [7]

Answer:

5 is the factor of 10. 5% of 10

6 0
3 years ago
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