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inysia [295]
3 years ago
11

Can someone help me?

Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

Not aplicatble=22

Step-by-step explanation:

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7. Use the properties of operations to simplify this algebraic expression. Rewrite the expression by following the directions in
Svetach [21]

Answer:

-x + -13

Step-by-step explanation:

Rewrite: 5(x – 4) + 3x – 9x + 7

Step 1: 5(x + –4) + 3x + –9x + 7

Step 2: 5x + -20 + 3x + –9x + 7

Step 3: 5x + 3x + –9x + -20 + 7

Step 4: -1x + -13

Step 5: -x + -13

3 0
3 years ago
Which number line shows |-3|, |-8| ,| -2| , and |5| ?
Aleks [24]
Well, the absolute value of a number would always be positive, which means the dots on the line is going to be on the right side of 0. In the choices, the only number line that qualifies is C.
4 0
3 years ago
IM BEGGING YOU PLS JUST PLS PLS PLS HELP
erma4kov [3.2K]

Answer:

ABC is more than 90 Degrees because it is an Obtuse Angle

ADC is less than 90 Degrees because it is an Acute Angle

I don't know the exact answer but I hope this helps you a little!

5 0
2 years ago
Read 2 more answers
to build the garden of your dreams you need 11 m^3 of coil containing 46% clay. you have two types of soil you can combine to ac
aivan3 [116]

Answer: 9m^3 of soil with 50% clay and 2m^3 of soil with 28% clay is required

Step-by-step explanation:

Let x represent the quantity of the soil containing 50% clay that you would use.

Let y represent the quantity of the soil containing 28% clay that you would use.

To build the garden of your dreams you need 11 m^3 of soil.

x + y = 11 - - - - - - - - -1

Since the soil must contain 46% clay, the total amount of clay required is 46/100 × 11 = 5.06 m^3.

you have two types of soil you can combine to achieve this: soil with 50% clay and soil with 28% clay. This means that the quantity of both soils required to achieve 5.06 m^3 will be

0.5x + 0.28y = 5.06 - - - - - - - -2

Substituting x = 11 - y into equation 1, it becomes

0.5(11 - y) + 0.28y = 5.06

5.5 - 0.5y + 0.28y = 5.06

- 0.5y + 0.28y = 5.06 - 5.5

- 0.22y = - 0.44

y = - 0.44/ -0.22 = 2

Substituting y = 2 into x = 11 - y, it becomes

x = 11 - 2 = 9

7 0
3 years ago
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine
salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

                                              f(x)=\frac{e^{\frac{-x}{1000} }}{1000}

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

              b. P(1000<x<2000) = 0.2325

              c. P(x<1000) = 0.6321

              d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = \int\limits^b_a {P(x)} \, dx

Then, for the electronic component, probability will be:

P(a<x<b) = \int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx

P(a<x<b) = \frac{1000}{1000}.e^{\frac{-x}{1000} }

P(a<x<b) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

a. For a component to last more than 3000 hours:

P(3000<x<∞) = e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = e^{-3}

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}

P(1000<x<2000) = e^{-2}-e^{-1}

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}

P(0<x<1000) = e^{-1}-1

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

0.1 = 1-e^\frac{-x}{1000}

-e^{\frac{-x}{1000} }=-0.9

{\frac{-x}{1000} }=ln0.9

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0
3 years ago
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