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kifflom [539]
3 years ago
12

Solve the system of equations below 4x+y=16 and 2x+3y=-2

Mathematics
2 answers:
astraxan [27]3 years ago
7 0
4x+y=16 multiply both sides by -3 and will get 
2x+3y=-2

-12x -3y = -48
   2x +3y = -2
--------------------------
-10x  0  = -50

-10x = -50

x = -50/(-10) = 5

x = 5 

4x+y=16
4*5+y=16
20+y=16

y = 16-20

y = -4

x = 5
y = - 4

hope helped 
Marianna [84]3 years ago
4 0

Answer: (5,-4) APEX!

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yawa3891 [41]

Answer: From Figure A to Figure B it’s 1/2

Step-by-step explanation:

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Section A
sesenic [268]
_______________________________
8 0
3 years ago
HELP PLS GIVING BRAINLIEST
Setler79 [48]

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

y = mx+b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

(0,1)\\(1, -2)

We found the slope:

m = \frac {y2-y1} {x2-x1}\\m = \frac {-2-1} {1-0} = \frac {-3} {1} = - 3

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y = -3x + b

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