Nicolas sold 86 newspapers on Monday 79 on Tuesday and 68 on Wednesday and 83 on Friday how many newspapers did Nicholas sell on
2 answers:
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Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that
For parts (a) and (b), you're given everything you need to determine
.
For part (c), if
and 
are mutually exclusive, then 
, so 
. If the given probability is 
, then you can find 
. But if this given probability is for the intersection, finding is impossible.
For part (d), if and are independent, then 
.
For parts (a) and (b), you're given everything you need to determine
For part (c), if
For part (d), if
Answer:
99% confidence interval for the given specimen is [3.4125 , 3.4155].
Step-by-step explanation:
We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.
Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.
Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;
P.Q. = ~ N(0,1)
where, = sample mean weighing of specimen =
= 3.414 g
= population standard deviation = 0.001 g
n = sample of specimen = 3
= population mean
<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>
So, 99% confidence interval for the population mean, is ;
P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level
of significance are -2.5758 & 2.5758}
P(-2.5758 < < 2.5758) = 0.99
P( <
<
) = 0.99
P( <
<
) = 0.99
<u>99% confidence interval for</u> = [
,
]
= [ ,
]
= [3.4125 , 3.4155]
Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].