Answer:
3t-9 >= 0
Step-by-step explanation:
Original function f(t)= square root 3t-9
There cannot be a negative in the radicand therefore 3t-9 cannot equal a negative number.
The longest two sides will be 4 each and the shortest two sides will be 2 each
Answer:
Step-by-step explanation:
3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)! which becomes:
23! / 18! = (23 * 22 * 21 * 20 * 19 * 18! divided by 18! which becomes:
(23 * 22 * 21 * 20 * 19)
the result is 4037880
i used my ti-84 to take 23! and divide it by 18! and i got 4037880.
this confirms the solution is correct.
