Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)




Substituting the first three equations into the fourth allows us to solve for

:

For each possible value of

, we get two corresponding critical points at

.
At these points, respectively, we get a maximum value of

and a minimum value of

.
Answer:
A
Step-by-step explanation:
m=y2-y1/x2-x1
4-2=2
6-3=3
2/3
hope this helps =3
Where’s the ratios that we can select? can you provide?
A=adult ticket s=student ticket
64a+132s=$1040
a=2s
128a+132s=$1040
260tickets=$1040
$1040/260=$4
s=$4 (1s=$4x1)
a=$8 (2s=$4x2)
132s=$528 (132x$4)
64a=$512 (64x$8)
TOTAL=$1040