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Kisachek [45]
3 years ago
13

Use a Pythagorean identity to rewrite the equation below using only the function sin θ. Then find the value of r if θ=30°,60°, a

nd 90°.
r=4*sinθ*cos^2θ

Please explain/show steps, thanks!
Mathematics
1 answer:
zepelin [54]3 years ago
6 0
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
r=4sin(\theta )cos^2(\theta )\implies r=4sin(\theta )[1-sin^2(\theta )]
\\\\\\
r=4sin(\theta )-4sin^3(\theta )\qquad \qquad 
\begin{cases}
r=4sin(30^o)-4sin^3(30^o)\\
r=4sin(60^o)-4sin^3(60^o)\\
r=4sin(90^o)-4sin^3(90^o)
\end{cases}

\bf \begin{cases}
r=4\left( \frac{1}{2} \right)-4\left( \frac{1}{2} \right)^3\\\\
r=4\left( \frac{\sqrt{3}}{2} \right)-4\left( \frac{\sqrt{3}}{2} \right)^3\\\\
r=4(1)-4(1)^3
\end{cases}\implies 
\begin{cases}
r=2-\frac{1}{2}\\\\
r=2\sqrt{3}-\frac{3\sqrt{3}}{2}\\\\
r=4-4
\end{cases}\implies 
\begin{cases}
r=\frac{1}{2}\\\\
r=\frac{\sqrt{3}}{2}\\\\
r=0
\end{cases}
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