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faust18 [17]
3 years ago
10

Which terms describe the figure shown?

Mathematics
1 answer:
WITCHER [35]3 years ago
8 0
I can’t help you with just this you need to add a picture or something sorry
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Which expression is equivalent to log 3(x+4)
larisa86 [58]

Answer:

log 3(x+4) = log 3 + log (x+4)

Step-by-step explanation:

Because 3(x+4) is a product, log 3(x+4) = log 3 + log (x+4).

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Which are true of the function f(x)=49(1/7)^x
Ira Lisetskai [31]

The Option (1),(4) and (5) are correct.

Step-by-step explanation:

The  function given to us  is : y= f(x) =49(1/7)^x

The following  statements  are true regarding the above function is

  • As you can see  that  the value of y(49)is defined for  all values of x , so the Domain is the set of all values of x , which is set of all real numbers.
  • X is defined for all values of y. So the Range of  all the values that y can take  is also set of all real numbers greater than zero, i.e y>0.
  • As x increased by 1, each y-value is one seventh of the previous y-value

8 0
3 years ago
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Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
19. Beth leaves her home on her bike, traveling down a long country road, at the rate of 8 mph. Her brother, Brandon, left 15 mi
Korolek [52]
30 minutes
hope this helped!
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