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ehidna [41]
3 years ago
9

An equation has solutions of m = _5 and m = 9. Which could be the equation?

Mathematics
2 answers:
Anni [7]3 years ago
5 0
I think the correct answer from the choices listed above is the first option. The equation (m + 5)(m - 9) = 0 has <span>solutions of m = -5 and m = 9. Hope this answers the question. Have a nice day. Feel free to ask more questions. Thank you.</span>
zhannawk [14.2K]3 years ago
5 0

Answer:

A. (m+5)(m-9)=0

Step-by-step explanation:

We have been given that an equation has solutions of m=-5 and m=9. We are asked to the equation, which represents these solutions.

Let us check our given choices:

A. (m+5)(m-9)=0

Using zero product property, we will get:

m+5=0\text{ (or) }m-9=0

m+5-5=0-5\text{ (or) }m-9+9=0+9

m=-5\text{ (or) }m=9

Therefore, option A is the correct choice.

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Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)
givi [52]

Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

Step-by-step explanation:

Since we have given that

y=x^{8sinx}

By using logarithmic on both sides we get,

log y= 8 sinx. logx

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Now, differentiating on both sides ,we get,

\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})

\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})

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6 0
3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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