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2 years ago

13

In an inventory-sale, a department store offers 60% off on the original price of their selected clothes. What fraction is taken

off the price?

1 answer:

Colt1911 [192]2 years ago

8 0

I believe three fifths would be taken off.

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5.4= 0.9x<br> A.6.3<br> B. 6<br> C. 7.3<br> D.12

Marat540 [252]

Answer:

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5.4=0.9x

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3 years ago

Read 2 more answers

The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What

Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that $\mu = 64.4, \sigma = 2.91$

Sample of 50 women

This means that $n = 50, s = \frac{2.91}{\sqrt{50}}$

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}$

$Z = 1.46$

$Z = 1.46$ has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0

2 years ago

Jack is working two summer jobs, making $22 per hour tutoring and making $9 per

konstantin123 [22]

Answer:

Step-by-step explanation:

4 0

3 years ago

What is the range of g(x) = 3|x − 1| − 1? A. (-∞, 1] B. [-1, ∞) C. [1, ∞) D. (-∞, ∞)

AVprozaik [17]

Answer:

B. [-1, ∞).

Step-by-step explanation:

g(x) = 3|x − 1| − 1

When x = 1 g(x) = 3(0) - 1 = -1.

As all negative vales of x will give positive values of |x - 1| then g(x) = -1 is its minimum value. The graph will be shaped like a letter V with the vertex at (1,-1).

Therefore the range is [-1, ∞).

6 0

3 years ago

A manufacturer produces widgets that are packaged in boxes of 100. The probability of a widget being defective is 0.021. Find th

gavmur [86]

Answer:

$\=x=2.1$

$\sigma=2.03$

Step-by-step explanation:

From the question we are told that:

Sample size $n=100$

Probability of a defective widget $P=0.021$

Generally the equation for binomial trial is mathematically given by

$q=1-p$

$q=1-0.021$

$q=0.979$

Since X is binomial random variable with functions of n and p,The equation of mean \=x

$\=x=E(x)$

Where

$E(x=n*p)$

$\=x=100*0.021$

$\=x=2.1$

Generally the equation for variance \sigma is mathematically given by

$\sigma=\sqrt{nqp}$

$\sigma=\sqrt{200*0.021*0.979}$

$\sigma=2.03$

7 0

2 years ago