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vlabodo [156]
3 years ago
12

Can someone give me a quick algebra lesson and solve this example for me?

Mathematics
2 answers:
Ad libitum [116K]3 years ago
5 0

Answer:

3x- 15+6x+2=41

or, 9x-13=41

or, 9x= 54

: x=6

Karolina [17]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

Hi there!

>>Do I subtract or add the coefficients with variables together?

Add the terms with variables. In this case, the terms with variables are 3x and 6x. The communicative property of addition still holds true, so 3x+6x and 6x+3x are the same.

Do NOT subtract terms. If you do, let's take the 3x and 6x from the example above, doing either 3x-6x or 6x-3x would lead to the wrong answer.

Note: if you encounter a situation where if you have let's say, the terms -3x and 17x, -3x+17 and 17x + -3x are exactly the same (commutative property of addition still holds true). DO NOT do 17x - -3x or -3x-17x! Those would lead to the wrong answer.

Now,

We are given the following equation:

3x-15+6x+2=41

And we want to solve it for x

As stated above, we ADD the terms with coefficients together. So 3x+6x=9x.

The same is true for the numbers without variables; -15+2=-13

On the left, we have:

9x-13=41

Add 13 to both sides to remove it from the left side

9x=54

Divide both sides by 9 to isolate x

x=6

Hope this helps!

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A survey of households in a small town showed that in 850 of 1,200 sampled households, at least one member attended a town meeti
Iteru [2.4K]

Answer:

Hence the confidence interval is ( 0.6745, 0.7422).

Step-by-step explanation:

Now the given are  

Sample size = n = 1200  

x = 850  

Sample proportion is  

\hat{p}=\frac{x}{n}=\frac{850}{1200}=0.7083  

We have to construct 99% confidence interval for the population proportion.  

Formula Used:  

(\hat{p}-E , \hat{p}+E)  

Here E is a margin of error.  

E =Zc\times\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}  

Zc = 2.58  

E =2.58\times\sqrt{\frac{0.7083*(1-0.7083)}{1200}}\\\\E=2.58\times\sqrt{0.000172}=0.0339  

So confidence interval is ( 0.7083 - 0.0339 , 0.7083 + 0.0339)

                                            = ( 0.6745 , 0.7422).

3 0
3 years ago
Another geometry question thanks!
Anettt [7]

For the given right triangle, we have:

  • L = 57°
  • ML = 4.5
  • NL  =  7.5
<h3>How to get the dimensions of the given triangle?</h3>

Here we have a right triangle, remember that the sum of the internal angles of a triangle must be 180°, then:

N + M + L = 180°

We can see that:

N = 37°

M = 90°

Then:

L = 180° - N - M = 180° - 37° - 90° = 53°

Also, if we step on N, the adjacent cathetus measures 6 units, then we can use the relations:

tan(37°) = (opposite cathetus)/(adjacent cathetus)

tan(37°) = ML/6

tan(37°)*6 = ML = 4.5

cos(37°) = (adjacent cathetus)/(hypotenuse)

cos(37°) = 6/NL

NL = 6/cos(37°) =  7.5

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

4 0
2 years ago
Find x.<br><br><br><br> Question 1 options:<br><br> 6<br><br><br> 3<br><br><br> 9<br><br><br> 12
fredd [130]
Maybe it’s 3 but it actually depends on the equation . . .
6 0
3 years ago
If you can help please do! Thank you!
Aleks [24]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a parallelogram bisect each other , then

CO = OA = b

DO = OB = a

(a)

CA = CO + OA = b + b = 2b

(b)

DC = DO + OC = a - b

(c)

CB = CO + OB = b + a = a + b

7 0
3 years ago
The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea
Furkat [3]

The mean of a sequence of numbers is the average.

The true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

The given parameters are:

\mathbf{Mean = m}

\mathbf{Size = n}

The mean of a dataset is calculated as:

\mathbf{Mean = \frac{\sum x}{Size}}

So, we have:

\mathbf{m = \frac{\sum x}{n}}

Multiply both sides by m

\mathbf{\sum x = mn}

When the sequence is split into two, we have:

\mathbf{\sum x_1 = m_1\times n_1}

\mathbf{\sum x_2 = m_2\times n_2}

Where:

\mathbf{\sum x_ = \sum x_1 + \sum x_2}

So, we have:

\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Hence, the true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Read more about mean and averages at:

brainly.com/question/16217700

8 0
3 years ago
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