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RideAnS [48]
3 years ago
11

The perimeter of a rectangle is 20 feet and the foot-measure of each side is a whole number. How many rectangles with different

shapes satisfy these conditions? 
Mathematics
1 answer:
Airida [17]3 years ago
7 0
Length= 9 width= 1
or
length= 8 width= 2
or
length= 7 width= 3
or
length= 6 width= 4
You might be interested in
How can you determine the difference between an arithmetic and geometric sequence if you are given the first 4 terms of the sequ
Bess [88]
Compute successive differences of the terms.

If they are all the same, the sequence is arithmetic and the common difference is the difference you have found.

If successive pairs of differences have the same ratio, the sequence is geometric and the common ratio is the ratio you have determined.


Example of arithmetic sequence:
  1, 3, 5, 7
Successive differences are 3-1 = 2, 5-3 = 2, 7-5 = 2. All the differences are 2, which is the common difference of the sequence.

Example of geometric sequence:
  1, -3, 9, -27
Successive differences are -3-1 = -4, 9-(-3) = 12, -27-9 = -36. These are not the same, so the sequence is not arithmetic. Ratios of successive pairs of differences are 12/-4 = -3, -36/12 = -3. These are the same, so the sequence is geometric with common ratio -3.
3 0
3 years ago
Read 2 more answers
Question 4 of 11
MAVERICK [17]
This would be A True, hope this helps !
7 0
3 years ago
What is the square root of 9/16, 9 to the power of two
lbvjy [14]

Answer:

\frac{3}{4} , 9

Step-by-step explanation:

\sqrt{9/16} = \sqrt{9} ÷ \sqrt{16} = \frac{3}{4}

\sqrt{9^2} = \sqrt{81} = 9


3 0
3 years ago
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
5 0
3 years ago
What does f(3) means ?
Butoxors [25]

F(x)=x^2+x+5  

then  

F(3) would be the function evaluated at x=3, or 17.

anytime you see F(3) it is just whatever formula you are looking at evaluated when the variable is equal to 3.

5 0
3 years ago
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