Look at Figure 7-10. Describe the movement of water in the experimental set-up. What will happen to the concentration of water o
1 answer:
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Answer:
24555 years
Explanation:
Data provided in the question:
Half life of carbon 14 = 5700 years
carbon present in the dead man = 5% of the original amount of carbon 14
Now,
let the initial Amount of carbon be 'A'
Therefore,
after half life
Amount of carbon =
Thus,
=
here,
k is the decay constant
t is the time = 5700 years
therefore,
1 =
or
0.5 =
taking natural log both the sides
-0.69314 = 5700k
or
k = - 0.000122
therefore,
for dead man Amount of carbon = 5% of A = 0.05A
thus,
0.05A =
or
0.05 =
taking natural log both the sides
we get
-2.995 = - 0.000122 × t
or
t = 24555.18 ≈ 24555 years