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Mariana [72]
3 years ago
10

Carbon dioxide is obtained from the air and changed into carbohydrates and oxygen during the process of

Biology
1 answer:
Alex Ar [27]3 years ago
7 0
Photosynthesis, in the chloroplasts of the cells
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"STx-producing bacteria cause over a million deaths a year, but treatment with antibiotics is not effective"
natita [175]

Answer: Despite the availability of antibiotics that lyse E coli cells, the reason this is NOT recommended in course of treatment is because the antimicrobial agents may trigger the lytic cycle and result in increased toxin expression.

Explanation:

Shiga toxin (Stx) are toxins which are produced by shiga toxin-producing Escherichia coli ( STEC). The antimicrobial agents may also trigger the lytic cycle and result in increased toxin expression.

7 0
3 years ago
Industrial melanism refers to the dark pigmentation that evolved in some insects giving them protective coloration on vegetation
Natalka [10]

Answer:

  • The frequency of the dominant allele, p =  0.542
  • The proportion of black moths that are heterozygous 2pq = 0.496

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (Homozygous dominant), 2pq (Heterozygous), q² (Homozygous recessive). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

  • p the dominant allelic frequency,
  • q the recessive allelic frequency,
  • p² the homozygous dominant genotypic frequency
  • q² the homozygous recessive genotypic frequency
  • 2pq the heterozygous genotypic frequency

In the exposed example, 79% of the moths of the species Biston betularia were black due to the presence of a dominant gene for melanism.

If the genotypic frequency of back moths is 0.79, then, by performing the following equation we can get the not-black moths genotypic frequency:

p² + 2pq + q² = 1

where p² is the homozygous dominant genotypic frequency, q² the homozygous recessive genotypic frequency, and 2pq is the heterozygous genotypic frequency.

As 0.79 is the phenotypic frequency of black moths, then this frequency equals p²+2pq.

Clearing the equation:

p² + 2pq + q² = 1

0.79 + q² = 1

q² = 1 - 0.79

q² = 0.21

The genotypic frequency of non-black moths is 0.21. So, from here we can calculate the allelic frequency:

q² = 0.21

q= v 0.21

q = 0.458

If 0.46 is the allelic frequency of non-black moths, then by clearing the equation p + q = 1, we can get the p allelic frequency:

p + q = 1

p + 0.458 = 1

p = 1 - 0.458

p = 0.542

  • The genotypic frequency p² = (0.542)² = 0.294
  • The heterozygote genotypic frequency

        2 x p x q = 2 x 0.542 x 0.458 = 0.496

Finally, we can check this answer by clearing the following equation:

p² + 2pq + q² = 1

0.294 + 0.496 + 0.21 = 1                  

4 0
3 years ago
What you know about laws of motion
Advocard [28]

Answer:

Look up brownian motion

3 0
3 years ago
Please hurry I need the right answer and I will give brainliest for the right answer no alien talk or file
kow [346]

Answer:

grasshopper

The organisms that eat the producers are the primary consumers. ... The primary consumers are herbivores (vegetarians

7 0
3 years ago
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In E. coli, DNA polymerases I and III differ in many regards. Which of the following statements is not accurate? In E. coli, DNA
Alexus [3.1K]

Answer: DNA polymerase I is able to proofread; DNA polymerase III is not.

Explanation:

Escherichia coli is a gram negative anaerobic bacteria that is found in the gastrointestinal tract of and humans and animals. Escherichia coli has 5 types of DNA polymerase.

a. Polymerase I is used to repair any damaged DNA and proof reading

b. Polymerase II is used in proof reading, DNA Replication and repairs.

c. Polymerase III is primarily responsible for DNA replication. It also has the ability to proof read.

d. Polymerase IV is used to change genetic information of Escherichia coli.

e. Polymerase V is used in DNA repair in Escherchia coli.

3 0
3 years ago
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