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leonid [27]
3 years ago
11

How many revolutions does a go kart with a wheel circumference of 62.8318 inches make in a 1609 m race? Please answer as quickly

as possible!
Mathematics
1 answer:
Rudiy273 years ago
3 0

Answer: 1008 revolutions

Step-by-step explanation:

1 revolution is equal to 2\pi r

To find how many revolutions the wheel makes, you must divide the distance traveled in the race between the circumference of the wheel

You must first convert 62.8318 in to meters.

We know that 1 inch is 0.0254 meters

Then

62.8318\ in*\frac{0.0254\ m}{1\ in}= 1.5959\ m

revolutions = \frac{1609}{1.5959}\\\\revolutions=1008.21\\

Finally The wheel made 1008.21 revolutions

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Complete the square to solve the equation below.
sasho [114]
Hello there!

x² + x = 7/4
x² + - 7/4 = 0

Now we gonna use the quadratic formula to find x
a= 1
b=1
c = -1.75

x = -b+/-√b² -4ac all of them divide by 2a
x = -(1)+/-√(1)² - (4)(1)(-1.75) all of them divide by 2(1)
x= -1+/-√8 all of them divide by 2
x = -1/2 + √2 or x = -1/2 - √2

The correct option is option C

I hope that helps!
4 0
4 years ago
Find all the zeroes of the polynomial function f(x)=x^3-5x^2+6x-30 using synthetic division.
WITCHER [35]
Write the coeeficientes of the polynomial in order:

  | 1   - 5   6   - 30
  |
  |
  |
------------------------

After some trials you probe with 5

   | 1   - 5       6     - 30
   |
   |
5 |        5      0       30
-----------------------------
     1     0      6        0 <---- residue

Given that the residue is 0, 5 is a root.

The quotient is x^2 + 6 = 0, which does not have a real root.

Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.
3 0
3 years ago
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
3 years ago
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