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leonid [27]
3 years ago
11

How many revolutions does a go kart with a wheel circumference of 62.8318 inches make in a 1609 m race? Please answer as quickly

as possible!
Mathematics
1 answer:
Rudiy273 years ago
3 0

Answer: 1008 revolutions

Step-by-step explanation:

1 revolution is equal to 2\pi r

To find how many revolutions the wheel makes, you must divide the distance traveled in the race between the circumference of the wheel

You must first convert 62.8318 in to meters.

We know that 1 inch is 0.0254 meters

Then

62.8318\ in*\frac{0.0254\ m}{1\ in}= 1.5959\ m

revolutions = \frac{1609}{1.5959}\\\\revolutions=1008.21\\

Finally The wheel made 1008.21 revolutions

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A car travels 10km southeast and then 15 km in a direction 60 degrees north of east. What is the magnitude of the car's resultan
Maurinko [17]

Answer: 15.85km

Step-by-step explanation:

The car starts at the point (0,0)

Let's define east as the positive x-axis and north as the positive y-axis.

first, the car travels 10km southeast, so the angle is -45° from the east.

Then the new position of the car is:

(10km*cos(-45°), 10km*sin(-45°)) = (7.07km, -7.07km)

Now, from this point the car travels 15km with an angle of 60° (counting from the east)

So the new position is:

(7.07km + 15km*cos(60°), -7.07km + 15km*sin(60°)) = (14.57km  , 5.91km)

The magnitude of a vector (x, y) is √(x^2 + y^2)

So the magnitude of the vector (14.57km  , 5.91km) is:

√((14.57km)^2 + (5.91km)^2) = 15.85km

4 0
3 years ago
b) 7 of these cuboids of side 3 cm are put together to make this shape. Find the surface area of this shape. (3) Total marks: 5
valentina_108 [34]

Answer:  504 cm^2

The surface area of the shape is:

3 3 * 3=9

9 * 7=63

63+9=72 * 7

=504cm^2

6 0
2 years ago
The value of the expression 23+32-3×4-52÷5+(7×4) is
svet-max [94.6K]

Answer:  23+32-3×4-52÷5+(7×4)= 60.6

Step-by-step explanation:

3 0
3 years ago
Find the degree measure of each angle in the triangle.
Alex777 [14]

Answer:

  • ∠R = 56°
  • ∠Q = 90°
  • ∠S = 34°

Step-by-step explanation:

The given triangle is a right angled triangle.

So, the angles in the triangle are :

  • 90°
  • (2x + 38)°
  • (5x - 11)°

Solving according to <u>angle sum property</u>,

Sum of all angles in a triangle is 180°

\longrightarrow 90° + (2x + 38)° + (5x - 11)° = 180°

\longrightarrow 117° + 7x = 180°

\longrightarrow 7x = 180° - 117°

\longrightarrow 7x = 63°

\longrightarrow x = 9

Angles =

\longrightarrow 2(9) + 38

\longrightarrow 56°

\longrightarrow 5(9) - 11

\longrightarrow 34°

  • ∠R = 56°
  • ∠Q = 90°
  • ∠S = 34°

The angles are 56°, 90° and 34°.

4 0
3 years ago
I don’t know what the answer to this question is , help
ipn [44]

Answer:

(4, 0)

Step-by-step explanation:

given the 2 equations

y = x - 4 → (1)

- 4x - 6y = - 16 → (2)

substitute y = x - 4 into (2)

- 4x - 6(x - 4) = - 16

- 4x - 6x + 24 = - 16

- 10x + 24 = - 16 ( subtract 24 from both sides )

- 10x = - 40 ( divide both sides by - 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = 4 - 4 = 0

solution is (4, 0)

3 0
3 years ago
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