Ask question

Ask question

All categories

Naddika [18.5K]

3 years ago

12

An employee works 35 regular hours during a workweek in September of 2020. The employee was hired twelve years ago, earns a sala

ry of $122,500/year and is exempt from the overtime provisions of the FLSA. To date, he has received no compensation beyond his annual salary. He has requested that his employer withhold 10% of gross pay, which is to be contributed to a 403(b) plan.Taxable income for federal income tax withholding = $Taxable income for social security tax = $Taxable income for medicare tax = $

1 answer:

gizmo_the_mogwai [7]3 years ago

8 0

Answer:

im fresh im hood

Step-by-step explanation:

i dont care about brainly

You might be interested in

The ratio of Isabella's money to Shane's money is 3:11. If Isabella has $33, how much money do Shane and Isabella have together?

Sergio039 [100]

The ratio of Isabella’s money to Shane’s money is 3:11

Isabella has $33.

We can make a proportion to solve for how much money Shane has.
A proportion is two ratios that are set equal to each other.

Let’s call Shane’s money ‘S’

We get this proportion:   3/11 = 33/x

If we cross multiply we get:
(33) * (11) = (3) * (x)

Simplifying it, we get:
363 = (3) * (x)

Divide both sides by 3, we get:
x = 121

However, the question asks how much money they have together.

Isabella + Shane = Total
33 + 121 = $154

<span>They have $154 together.</span>

6 0

3 years ago

Read 2 more answers

The number of students enrolled at a college is 17,000 and grows 6% each year.

Ad libitum [116K]

Answer:

1020 new students per year.

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ME!!Write the quotient as a mixed number.<br> 46 divided by 9 = 5 R1

Zigmanuir [339]

Answer:

$5\frac{1}{9}$

Step-by-step explanation:

When dividing 46 by 9 quotient is 5 and remainder is 46 - 45 = 1

$5\frac{1}{9}$

5 0

3 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

or

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so:

$\theta\neq \pi$

having said this, we can now start solving the equation:

$tan(\frac{\theta}{2})=sin(\theta)$

we can start solving this equation by using the half angle formula, such a formula tells us the following:

$tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}$

so we can substitute it into our equation:

$\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)$

we can now multiply both sides of the equation by $sin(\theta)$

so we get:

$1-cos(\theta)=sin^{2}(\theta)$

we can use the pythagorean identity to rewrite $sin^{2}(\theta)$ in terms of cos:

$sin^{2}(\theta)=1-cos^{2}(\theta)$

so we get:

$1-cos(\theta)=1-cos^{2}(\theta)$

we can subtract a 1 from both sides of the equation so we end up with:

$-cos(\theta)=-cos^{2}(\theta)$

and we can now add $cos^{2}(\theta)$

to both sides of the equation so we get:

$cos^{2}(\theta)-cos(\theta)=0$

and we can solve this equation by factoring. We can factor $cos(\theta)$ to get:

$cos(\theta)(cos(\theta)-1)=0$

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

$cos(\theta)=0$

$\theta=cos^{-1}(0)$

$\theta={\frac{\pi}{2}, \frac{3\pi}{2}}$

Equation 2:

$cos(\theta)-1=0$

we add a 1 to both sides of the equation so we get:

$cos(\theta)=1$

$\theta=cos^{-1}(1)$

$\theta=0$

so we end up with three answers to this equation:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

7 0

3 years ago

Solve -9/2y = 27/2 for y

slavikrds [6]

Answer: y = -3

I hope this helps you

4 0

3 years ago