Answer:
60%
Step-by-step explanation:
You can solve this problem by setting up a system of equations.
Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:
0.4x+0.2y=160
x+y=500
Now, you can multiply the first equation by 5 on both sides to get:
2x+y=800
Subtracting the second equation from the first equation now yields:
x=300
y=200
Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!
First get n's by them selves
-6 = 10n -4n (remember to always change sign when crossing the equals sign.
-6 = 6n ( subtract and take sign of the larger) ( then divide both sides by 6 to solve for n)
-1 = n
hope this helps
Answer:
x = 31.2
Step-by-step explanation:
x - 19.7 = -4.1
x = 15.6 --- add 19.7 to both sides to get rid of -19.7
x = 31.2 --- multiply both sides by 2 to get rid of
5/3=1.6666 hope this helpssssssssssssssssssss
You get everything you need from factoring the last expression:
The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with
Plug in everything you know and solve for 
:
