Answer:


Step-by-step explanation:
Use the trigonometry formula

You are given that

Substitute into the first formula

Angle
is acute angle, then the sine of this angle is positive and

5 x 7 because if 5 is the width is 25 then 18 minus that is 7 and 7x5 = 35
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer: C. 70 percent
Step-by-step explanation:
Given, Time for the first unit = 50 minutes
Time for the second unit = 35 minutes
The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.
So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.
Hence, the correct option is "C. 70 percent".
Answer:
look at the domain, where the line is on the x-axis
Step-by-step explanation: