1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flura [38]
3 years ago
11

Only need help with 6. And 8.

Mathematics
2 answers:
DENIUS [597]3 years ago
5 0
Some type or liters and oz
Sladkaya [172]3 years ago
4 0
6.42 gal = 158.99L
8.15 kg = 529.11oz
You might be interested in
Please help me on this I’m so tired and I can’t sleep until my progress is at 80 and this is the end of my year it’s at 79%
Mice21 [21]

Answer: The bottom one is the answer

Step-by-step explanation:

The one on the right wouldn't be correct because histograms are supposed to always be connected from the beginning of it.

The one on the left is ignoring the fact that 40-59 and 60-79 are two different periods of minutes.

So the only correct on would be the bottom one.

5 0
3 years ago
The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the pop
NikAS [45]

Answer:

  • p(t) = 100×1.0153^(12t)
  • 1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

5 0
2 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark a lot of points !!!!!!!!
soldi70 [24.7K]

Answer:

here it is

Step-by-step explanation:

3 0
2 years ago
HUUURRRYYYY PLEASEEEEE!!!!!!!What is the approximate volume of a cone with a height of 6 mm and radius of 18 mm? Use 3.14 to app
bulgar [2K]
V=pir^2(h/3)
V= 3.14x18^2x6/3
V= about <span>2034.72</span>
3 0
3 years ago
There are 1,570 souvenir paperweights that need to be packed in boxes. Each box will hold 17 paperweights. How many boxes will b
arlik [135]

Answer:

93 boxes will be needed.

Step-by-step explanation:

Divide 1570 ÷ 17

This gives the answer 92.35

So 92 boxes won't be enough. 0.35 of a box itsn't helpful in the real world. So you need 93 boxes.

8 0
2 years ago
Other questions:
  • The annual per capita consumption of bottled water was 34.734.7 gallons. assume that the per capita consumption of bottled water
    11·1 answer
  • A 5% destroys solution is given intravenously. Suppose a total of 2.64 L of the solution is given over a 19-hour period. What is
    7·1 answer
  • the volume of a rectangular prism with base dimensions of 3 cm and 8 cm and a prism height of 12 cm is?
    7·1 answer
  • A basketball team has scored 60 points in their first 5 games. If this trend were to continue, how many points would you expect
    13·1 answer
  • What is the inequality
    14·1 answer
  • A video is 2 hours long. How many minutes long is the video?
    9·1 answer
  • Really confused on this.
    12·2 answers
  • Forty four grams are equivalent to how many ounces to the nearest hundredth?
    5·1 answer
  • How can 10% of 45 be used to determine 30% of 45?
    5·2 answers
  • The question is below.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!