A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
The double bar graph shows the number of imports and exports for a company in a certain week.
On how many days was the number of exports greater than the number of imports?
Answer: From the given double bar graph, we clearly see:
Number of imports for a company on Monday = 15
Number of exports for a company on Monday = 7
Number of imports for a company on Tuesday = 18
Number of exports for a company on Tuesday = 9
Number of imports for a company on Wednesday = 14
Number of exports for a company on Wednesday = 14
Number of imports for a company on Thursday = 15
Number of exports for a company on Thursday = 6
Number of imports for a company on Friday = 9
Number of exports for a company on Friday = 19
From the above information, we clearly see that only on Friday the number of exports are greater than number of imports. Therefore, there is only 1 day when the number of exports greater than the number of imports.
Hence the option D. 1 is correct
A scale factor of 3 was used
Answer:
17.65% probability a rider must wait between 1 minute and 1.5 minutes
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is between c and d is given by the following formula

For this problem, we have that:


17.65% probability a rider must wait between 1 minute and 1.5 minutes
Answer:
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Step-by-step explanation: