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2 years ago

In simplest radical form, what are the solutions to the quadratic equation 6 = x^2 - 10x

Mathematics

1 answer:

Andre45 [30]2 years ago

4 0

Answer:

The solution set is {5 + √31, 5 - √31}.

Step-by-step explanation:

6 = x^2 - 10x

x^2 - 10x = 6

Completing the square:-

(x - 5)^2 - 25 = 6

Adding 25 to both sides:-

(x - 5)^2 = 31

Taking square roots:-

x - 5 = +/- √31

Solutions are x = 5 + √31, 5 - √31

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2 years ago

Read 2 more answers

There are nickels, dimes, quarters in a large piggy bank, for every 2 nickels there are 3 dimes, for every 2 dimes there are 5 q

Alex

There are 80 nickels and 120 dimes and 300 quarters in piggy bank

Solution:

Given that,

For every 2 nickels there are 3 dimes ,

So, ratio of nickel to dime will be 2 : 3

Also for every 2 dimes there are 5 quarters

So, ratio of dime to quarters is 2 : 5

Let us first find the ratio of nickles to dimes to quarters

nickel : dime = 2 : 3

dime : quarters = 2 : 5

$\frac{nickel}{dime} = \frac{2}{3}$

$nickel = \frac{2}{3} dime$

$\frac{dime}{quarter} = \frac{2}{5}$

$quarter = \frac{5}{2}dime$

So,

$nickel : dime : quarter = \frac{2}{3}dime : dime : \frac{5}{2}dime\\\\nickel : dime : quarter = \frac{2}{3} : 1 : \frac{5}{2}\\\\nickel : dime : quarter = 4 : 6 : 15$

Thus nickel : dime : quarters = 4 : 6 : 15

Now, let the number of nickel be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

From given question,

There are 500 coins in all.

number of nickel + number of dimes + number of quarters = 500

4x + 6x + 15x = 500

25x = 500

x = 20

Thus,

number of nickel = 4x = 4(20) = 80

number of dimes = 6x = 6(20) = 120

number of quarters = 15x = 15(20) = 300

Thus there are 80 nickels and 120 dimes and 300 quarters in piggy bank

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