$x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \ \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6$

3 0

3 years ago

What do you do when ur bathtub wont work

lubasha [3.4K]

Answer:

Sometimes I l i c k myself like a cat but other times I'll just get orange juice and pour it on myself. Either way works great!

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Select the correct answer. Which of the following is a solution to ? A. B. C. D. E.

Leni [432]

Answer:

the answer to your question is A

3 0

2 years ago

Read 2 more answers

How do you make 'a' the subject of the formula: ab - cd = ac

xxTIMURxx [149]

First bring all terms in 'a' to the left side of the formula by subtracting ac from both sides

ab - ac - cd = ac - ac
ab - ac - cd = 0
now add cd to both sides
ab - ac -cd + cd = cd
ab - ac = cd
now factor the left side by taking out the 'a'
a(b-c) = cd
now divide both sides by (b-c)
a = cd / (b-c)
done

3 0

3 years ago