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Iteru [2.4K]
3 years ago
9

What is decimal expansion of

lt="\frac{284}{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
The answer is 94.6 I hope this helped and you didn’t find the answer yet
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Jacob is a teacher. He made 75 cookies to give to his students on the first day of school. He gave 2 cookies to each student who
Lisa [10]

Answer:

See explanation

Step-by-step explanation:

Jacob has 75 cookies.

He gave 2 cookies to each student.

Complete the table:

\begin{array}{cc}\text{Number of student arrived}&\text{Number of cookies left}\\1&75-2=73\\2&73-2=71\\3&71-2=69\\...&...\end{array}

Let n be the number of students. After nth student arrived Jacob had left

g(n)=75-2n

cookies.

This is an arithmetic sequence with

g_1=g(1)=73\\ \\d=-2

Thus,

g_{n}=g_{n-1}-2\\ \\g(n)=g(n-1)-2

3 0
3 years ago
Read 2 more answers
Prime factor tree of 385
timama [110]


11*5*7 

385 breaks down to 7 and 55. Bring the seven down. Break 55 down to 11 and 5. Then bring those down and you get 11*5*7

4 0
3 years ago
What is the slope of y = 4x - 3
Gre4nikov [31]

Answer:

4

Step-by-step explanation:

Slope-intercept form is y = mx + c

m is the slope

c is the intercept

In this case, m = 4.

Therefore, 4 is the slope.

Can I get brainliest

3 0
3 years ago
(I WILL MARK BRAINLY)
Mademuasel [1]

Answer:

Step-by-step explanation:

light blue, 4,6,8

5 0
3 years ago
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances
wariber [46]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to compare two compounds, designed to reduce braking distance, used in tire manufacturing to prove if the braking distance of SUV's equipped with tires made with compound 1 is shorter than the braking distance of SUV's equipped with tires made with compound 2.

So you have 2 independent populations, SUV's equipped with tires made using compound 1 and SUV's equipped with tires made using compound 2.

Two samples of 81 braking tests are made and the braking distance was measured each time, the study variables are determined as:

X₁: Braking distance of an SUV equipped with tires made with compound one.

Its sample mean is X[bar]₁= 69 feet

And the Standard deviation S₁= 10.4 feet

X₂: Braking distance of an SUV equipped with tires made with compound two.

Its sample mean is X[bar]₂= 71 feet

And the Standard deviation S₂= 7.6 feet

We don't have any information on the distribution of the study variables, nor the sample data to test it, but since both sample sizes are large enough n₁ and n₂ ≥ 30 we can apply the central limit theorem and approximate the distribution of both variables sample means to normal.

The researcher's hypothesis, as mentioned before, is that the braking distance using compound one is less than the distance obtained using compound 2, symbolically: μ₁ < μ₂

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

The statistic to use to compare these two populations is a pooled Z test

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } }

Z ≈ N(0;1)

Z_{H_0}= \frac{69-71-0}{\sqrt{\frac{108.16}{81} +\frac{57.76}{81} } }= -1.397

The rejection region if this hypothesis test is one-tailed to the right, so you'll reject the null hypothesis to small values of the statistic. The critical value for this test is:

Z_{\alpha  } = Z_{0.05}= -1.648

Decision rule:

If Z_{H_0} > -1.648 , then you do not reject the null hypothesis.

If Z_{H_0} ≤ -1.648 , then you reject the null hypothesis.

Since the statistic value is greater than the critical value, the decision is to not reject the null hypothesis.

At a 5% significance level, you can conclude that the average braking distance of SUV's equipped with tires manufactured used compound 1 is greater than the average braking distance of SUV's equipped with tires manufactured used compound 2.

I hope you have a SUPER day!

4 0
3 years ago
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