Question

Which exponential function has an initial value of 2? f(x) = 2(3x) f(x) = 3(2x)

Answer 1

Answer:

X=2 F=6 This works for both equations. Hope this helps!

Step-by-step explanation:

Answer 2

Answer:

The exponential function $f(x)=2(3^x)$ has an initial value of 2. The correct option is 1.

Step-by-step explanation:

The general form of an exponential function is

$g(x)=ab^x$

Where, a is initial value and b is growth or decay factor.

In option 1, the given function is

$f(x)=2(3^x)$

Here, the initial value is 2 and growth factor is 3. Therefore the correct option is 1.

In option 2, the given function is

$f(x)=3(2^x)$

Here, the initial value is 3 and growth factor is 2. Therefore option 2 is incorrect.