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4 years ago

Which exponential function has an initial value of 2? f(x) = 2(3x) f(x) = 3(2x)

Mathematics

2 answers:

Phoenix [80]4 years ago

8 0

Answer:

X=2 F=6 This works for both equations. Hope this helps!

Step-by-step explanation:

andrezito [222]4 years ago

7 0

Answer:

The exponential function $f(x)=2(3^x)$ has an initial value of 2. The correct option is 1.

Step-by-step explanation:

The general form of an exponential function is

$g(x)=ab^x$

Where, a is initial value and b is growth or decay factor.

In option 1, the given function is

$f(x)=2(3^x)$

Here, the initial value is 2 and growth factor is 3. Therefore the correct option is 1.

In option 2, the given function is

$f(x)=3(2^x)$

Here, the initial value is 3 and growth factor is 2. Therefore option 2 is incorrect.

You might be interested in

For a least squares regression line, the sum of the residuals is __________.

Westkost [7]

Answer:

d. always zero.

Step-by-step explanation:

A least squares regression line is a standard technique in regression analysis used to make the vertical distance obtained from the data points running to the regression line to become very minimal or as small as possible.

For a least squares regression line, the sum of the residuals is always zero.

Basically, residuals are used to measure or determine whether or not the line of regression is a good fit or match for the data by subtracting the difference between them i.e the predicted y value and the actual y value, for the x value respectively.

3 0

3 years ago

A quality control inspector has drawn a sample of 10 light bulbs from a recent production lot. Suppose 20% of the bulbs in the l

Neko [114]

Answer:

The probability is 0.0008.

Step-by-step explanation:

Let X represents the event of defective bulb,

Given, the probability of defective bulb, p = 20 % = 0.2,

So, the probability that bulb is not defective, q = 1 - p = 0.8,

The number of bulbs drawn, n = 10,

Since, binomial distribution formula,

$P(x=r) = ^nC_r p^r q^{n-r}$

Where, $^nC_r = \frac{n!}{r!(n-r)!}$

Hence, the probability that exactly 7 bulbs from the sample are defective is,

$P(X=7)=^{10}C_7 (0.2)^7 (0.8)^{10-7}$

$=120 (0.2)^7 (0.8)^3$

$=0.000786432$

$\approx 0.0008$

6 0

3 years ago

Factor this expression completely. 36y2 - 1

shtirl [24]

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

= (6y - 1)(6y + 1)

5 0

4 years ago

Read 2 more answers

Help Please.. Can't figure it out

Alex787 [66]

Answer: